2013-04-18 25 views
1

我想创建一个春天休息服务。我servlet.xml中像下面:Xstream marshaller没有unmarshelling XML帖子身体

<beans xmlns="http://www.springframework.org/schema/beans" 
xmlns:context="http://www.springframework.org/schema/context" 
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:util="http://www.springframework.org/schema/util" 
xsi:schemaLocation=" 
    http://www.springframework.org/schema/beans  
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 
    http://www.springframework.org/schema/context 
    http://www.springframework.org/schema/context/spring-context-3.0.xsd 
    http://www.springframework.org/schema/mvc 
    http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> 

    <bean class="org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor"/> 


<!-- Database Configuration --> 
<import resource="classpath:DataSource.xml"/> 
<import resource="classpath:Hibernate.xml"/> 

<!-- Beans Declaration --> 
<import resource="classpath:Employee.xml"/> 

<context:component-scan base-package="com.nilenium.service.controller" /> 

<mvc:annotation-driven /> 

     <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> 
    <property name="messageConverters"> 
    <list> 
    <ref bean="jsonConverter"/> 
    <ref bean="marshallingHttpMessageConverter"/> 
    </list> 
    </property> 
    </bean> 

    <bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"></bean> 


    <bean id="xstreamMarshaller" class="org.springframework.oxm.xstream.XStreamMarshaller"> 
    <property name="autodetectAnnotations" value="true"/> 
    <property name="annotatedClasses"> 
    <list> 
     <value>com.nilenium.employee.model.Employee</value>       
     <value>com.nilenium.employee.model.EmployeeRecord</value>       
    </list>      
    </property> 

</bean> 

    <bean id="marshallingHttpMessageConverter" 
     class="org.springframework.http.converter.xml.MarshallingHttpMessageConverter"> 
    <property name="marshaller" ref="xstreamMarshaller"/> 
    <property name="unmarshaller" ref="xstreamMarshaller"/> 
</bean> 



    <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver"> 
<property name="order" value="1" /> 
    <property name="ignoreAcceptHeader" value="true" /> 
<property name="defaultContentType" value="application/json" /> 
    <property name="mediaTypes"> 
<map> 
<entry key="json" value="application/json" /> 
<entry key="xml" value="application/xml" /> 
</map> 
</property> 

<property name="defaultViews"> 
<list> 
<!-- JSON View --> 
<bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" /> 

<!-- XML View --> 
<bean class="org.springframework.web.servlet.view.xml.MarshallingView"> 
<constructor-arg> 
    <bean class="org.springframework.oxm.xstream.XStreamMarshaller"> 
    <property name="autodetectAnnotations" value="true"/> 
    <property name="aliases"> 
    <props> 
    <prop key="employee">com.nilenium.employee.model.Employee</prop> 
    <prop key="employee">com.nilenium.employee.model.EmployeeRecord</prop> 
    </props> 
</property> 
    </bean> 
</constructor-arg> 
</bean> 
    </list> 
    </property> 
</bean> 


</beans> 

而且我的模型类是这样的:

package com.nilenium.employee.model; 

import java.io.Serializable; 

import org.codehaus.jackson.annotate.JsonProperty; 
import org.codehaus.jackson.map.annotate.JsonRootName; 

import com.thoughtworks.xstream.annotations.XStreamAlias; 


@XStreamAlias("employee") 

public class Employee implements Serializable { 

private static final long serialVersionUID = 1L; 


private int employeeId; 
private String employeeName; 

public int getEmployeeId() { 
    return employeeId; 
} 

public void setEmployeeId(int employeeId) { 
    this.employeeId = employeeId; 
} 

public String getEmployeeName() { 
    return employeeName; 
} 

public void setEmployeeName(String employeeName) { 
    this.employeeName = employeeName; 
} 



public Employee(int employeeId, String employeeName) 
{ 
    this.employeeId = employeeId; 
    this.employeeName = employeeName; 

} 
public Employee() { 
} 
} 

我的服务控制器类是这样的:

package com.nilenium.service.controller; 

import java.util.List; 
import javax.servlet.http.HttpServletResponse; 
import org.springframework.beans.factory.annotation.Autowired; 
import org.springframework.stereotype.Controller; 
import org.springframework.ui.ModelMap; 
import org.springframework.web.bind.annotation.ExceptionHandler; 
import org.springframework.web.bind.annotation.PathVariable; 
import org.springframework.web.bind.annotation.RequestBody; 
import org.springframework.web.bind.annotation.RequestMapping; 
import org.springframework.web.bind.annotation.RequestMethod; 
import org.springframework.web.bind.annotation.ResponseBody; 

import com.nilenium.employee.bo.EmployeeBo; 
import com.nilenium.employee.model.Employee; 
import com.nilenium.employee.model.EmployeeRecord; 

@Controller 
@RequestMapping("/Service") 
public class NileniumServiceController { 

@Autowired 
private EmployeeBo employeeBo; 

@ExceptionHandler 
public String exceptionHandler(Exception e){ 
    return "serviceError"; 
} 

@RequestMapping(value = "employeeId/{employeeId}", method = RequestMethod.GET, headers = "Accept=application/xml, application/json") 
public Employee getEmployeeName(@PathVariable int employeeId, 
     HttpServletResponse resp, 
     ModelMap model) { 
//  System.out.println("Emp Name : " + employeeName); 
    Employee empReturned = new Employee(); 
    empReturned.setEmployeeId(employeeId); 
    empReturned.setEmployeeName("Demo Name"); 

    return empReturned; 

} 

@RequestMapping(value = "/employees", method = RequestMethod.GET, headers = "Accept=application/xml, application/json") 
public EmployeeRecord getAllEmployeeDetails(HttpServletResponse resp, 
     ModelMap model) { 

    List<Employee> empListReturned = employeeBo.getAllEmployee(); 
    EmployeeRecord eRecords = new EmployeeRecord(); 
    eRecords.setEmployeeList(empListReturned); 
    return eRecords; 
} 

@RequestMapping(value = "/storeemployee",method = RequestMethod.POST, headers = {"Accept=text/xml, application/json"}) 
public Employee storeEmpRecord(@RequestBody Employee employee,HttpServletResponse resp, 
     ModelMap model) 
{ 
    System.out.println("Emp Id received : "+employee.getEmployeeId()); 
    System.out.println("Emp Name received : "+employee.getEmployeeName()); 
//  Employee empReturned = employeeBo.findByEmployeeId(1); 


    return employee; 
} 

} 

当我试图将xml发布到storeEmpRecord方法xstream编组无法将xml请求转换为相应的对象(Employee对象)。

我的测试客户端是这样的:

package com.nilenium.test; 

import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStream; 
import java.io.InputStreamReader; 
import java.io.UnsupportedEncodingException; 
import java.net.URISyntaxException; 

import org.apache.http.HttpEntity; 
import org.apache.http.HttpException; 
import org.apache.http.HttpResponse; 
import org.apache.http.client.HttpClient; 
import org.apache.http.client.methods.HttpPost; 
import org.apache.http.entity.StringEntity; 
import org.apache.http.impl.client.DefaultHttpClient; 
import org.springframework.aop.framework.adapter.DefaultAdvisorAdapterRegistry; 

import com.nilenium.employee.model.Employee; 
import com.thoughtworks.xstream.XStream; 
import com.thoughtworks.xstream.io.xml.DomDriver; 

public class RestPostTest { 
public static void main(String[] args) { 
Employee emp = new Employee(); 
emp.setEmployeeId(1); 
emp.setEmployeeName("Nilalohita"); 

XStream xStream = new XStream(new DomDriver()); 
xStream.alias("employee", Employee.class); 
System.out.println(xStream.toXML(emp)); 
String xmlBody = xStream.toXML(emp); 
HttpClient client = new DefaultHttpClient(); 
String jsonDemo = "{\"employeeId\":2,\"employeeName\":\"He-Man\"}"; 
try { 
    HttpPost post = new HttpPost("http://localhost:8080/SampleMaven/Service/storeemployee"); 
//  post.addHeader("Accept", "application/json"); 
//  post.addHeader("Content-Type", "application/json"); 

    post.addHeader("Accept", "application/xml"); 
    post.addHeader("Content-Type", "application/xml"); 

    StringEntity entity = new StringEntity(xmlBody, "UTF-8"); 
//  entity.setContentType("application/json"); 
    entity.setContentType("application/xml"); 
    post.setEntity(entity); 

    HttpResponse response = client.execute(post); 

    BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); 
     String line = ""; 
     while ((line = rd.readLine()) != null) { 
     System.out.println(line); 
     } 


} catch (URISyntaxException e) { 
    // TODO Auto-generated catch block 
    e.printStackTrace(); 
} catch (UnsupportedEncodingException e) { 
    // TODO Auto-generated catch block 
    e.printStackTrace(); 
} catch (HttpException e) { 
    // TODO Auto-generated catch block 
    e.printStackTrace(); 
} catch (IOException e) { 
    // TODO Auto-generated catch block 
    e.printStackTrace(); 
} 
} 
} 

请让我知道,如果我做错了什么。同样的事情是为员工类使用@XMLroot而不是@XStreamAlias("employee")为jaxb工作。

我收到以下错误。完整的堆栈跟踪是这样

Caused by:</h3><pre>javax.servlet.ServletException: Unable to locate object to be marshalled in model: {} 
    at org.springframework.web.servlet.view.xml.MarshallingView.renderMergedOutputModel(MarshallingView.java:100) 
    at org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:250) 
at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1047) 
at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:817) 
at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:719) 
at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:644) 
at org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:560) 
at javax.servlet.http.HttpServlet.service(HttpServlet.java:727) 
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820) 
at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:487) 
at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:362) 
at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) 
at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181) 
at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:726) 
at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405) 
at org.mortbay.jetty.handler.ContextHandlerCollection.handle(ContextHandlerCollection.java:206) 
at org.mortbay.jetty.handler.HandlerCollection.handle(HandlerCollection.java:114) 
at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) 
at org.mortbay.jetty.Server.handle(Server.java:324) 
at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:505) 
at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:843) 
at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:648) 
at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:205) 
at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380) 
at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395) 
at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488) 
+0

您能更具体地了解您遇到的错误吗?堆栈跟踪? – Magnilex

+0

我收到以下错误无法找到要在模型中编组的对象:{} – user2296195

回答

0

的问题是在控制器方法:

@RequestMapping(value = "/storeemployee",method = RequestMethod.POST, headers = {"Accept=text/xml, application/json"}) 
public Employee storeEmpRecord(@RequestBody Employee employee,HttpServletResponse resp, 
    ModelMap model) 
{ 
    System.out.println("Emp Id received : "+employee.getEmployeeId()); 
    System.out.println("Emp Name received : "+employee.getEmployeeName()); 
//  Employee empReturned = employeeBo.findByEmployeeId(1); 
return employee; 
} 

Spring MVC的不(不能)自动添加对象model。您需要将employee对象添加到ModelMap。然后将模型映射传递给编组视图,该编组视图查找可以编组的任何对象,然后编组它们以进行响应。

Unable to locate object to be marshalled in model: {}意味着编组视图收到一个没有包含XStream标注的对象的ModelMap。

希望这会有所帮助。

+0

我会试试这个......感谢信息..但是如果我使用JAXB,同样的控制器工作正常..只需要将@xmlroot为类将被编组或解组... ...但任何如何..谢谢你的建议.. :) – user2296195