ORA-00905：缺少关键字

Question

我的表有这些列：

|blo|NotionalCurrency|Notional|Premiumcurrency|Basecurrency|Termcurrency|StructureName|Basemarketprice|Termmarketpriceprecent |Termmarketprice| 

我想从这些获得BLO，货币和价格。下面是我的SQL：

select blo.opt, 
    case 
    when opt.premiumcurrency is not null and opt.structurename is not null then currency = opt.premiumcurrency 
     case 
     when opt.notionalcurrency = opt.basecurrency and opt.premiumcurrency = opt.termcurrency then price = opt.termmarketpricepercent/opt.notional 
     else 
      case 
      when opt.premiumcurrency = opt.basecurrency then price = opt.basemarketprice /100 
      else 
      price = opt.termmarketpriceprecent /100 
      end 
     end 
    when price = 0 then price = 0.000001 
    end 
FROM interface opt 
WHERE opt.notionalcurrency = opt.basecurrency and opt.premiumcurrency = opt.termcurrency; 

，但我得到的错误：ORA-00905: missing keyword

基本上，下面的逻辑应该被用来获取/导出SQL让三列：BLO，货币及价格：

If notional currency = base currency and premium currency=term currency Then 
       Price =term market price/notional 
       currency = notional currency 
Else 
       If notional currency = premium currency then 
           Price= base market price /100 
           currency = termcurrency 
       else 
           Price=term market price percent /100 
           currency = notional 
       end if 
end if 
if price=0 then 
price=0.000001 
end if 

Answer 1

这里有很多问题。将它分解一下：

case 
    when opt.premiumcurrency is not null 
    and opt.structurename is not null 

从where条件，opt.premiumcurrency可以使检查不加入任何不能为空。

then currency = opt.premiumcurrency 

您不能在此处设置值;如Arka所示，看起来您希望这是一个在最终输出中标记为currency的表达式。

 case 
     when opt.notionalcurrency = opt.basecurrency 
     and opt.premiumcurrency = opt.termcurrency 
     then price = opt.termmarketpricepercent/opt.notional 

现在你要找的价格，而不是货币，所以这不是以前的情况子句的一部分;这意味着你现在应该有一个end as currency,。但是，您也没有else条件，这意味着如果opt.structurename为空，您的货币表达式将为空;不清楚这是否是你想要的。

但是由于您的where子句，这两个条件都必须是真的，这使得整个case是多余的。再次，您需要一个表达式别名，而不是尝试使用=设置值。

 else 
      case 
      when opt.premiumcurrency = opt.basecurrency 
      then price = opt.basemarketprice /100 
      else 
      price = opt.termmarketpriceprecent /100 
      end 
     end 

你在这里嵌套的情况下，所以它看起来像你想转换一个if/ELSIF /其他直接构造，而没有考虑case语义是如何工作的。当/ end可以作为封闭情况的一部分时，不需要嵌套的case/end。但是如上所述，第一个when的条件总是必须是真的，并且opt.premiumcurrency = opt.basecurrency也必须是真实的，所以这些都是多余的。

when price = 0 then price = 0.000001 

这只是漂浮在那里，所以这需要有一个外壳或解码，或者可能是一个least()如果该值永远不会是负的。

所以与where条件你表明，这可以简化为：

select opt.blo, 
    case 
    when opt.structurename is not null then opt.premiumcurrency 
    end as currency, 
    case 
    when opt.termmarketpricepercent = 0 then 0.000001 
    else opt.termmarketpricepercent/opt.notional 
    end as price 
from interface opt 
where opt.notionalcurrency = opt.basecurrency 
and opt.premiumcurrency = opt.termcurrency; 

如果where条款是暂时的，你需要一个更一般的查询，则它仍然是简单的比你使它：

select opt.blo, 
    case 
    when opt.premiumcurrency is not null 
     and opt.structurename is not null 
     then opt.premiumcurrency 
    end as currency, -- still no 'else' so null if structurename is null 
    decode (
     case 
     when opt.notionalcurrency = opt.basecurrency 
      and opt.premiumcurrency = opt.termcurrency 
      then opt.termmarketpricepercent/opt.notional 
     when opt.premiumcurrency = opt.basecurrency 
      then opt.basemarketprice /100 
     else opt.termmarketpricepercent /100 
     end, 0, 0.000001) as price 
from interface opt; 

（我交换blo.opt到opt.blo作为沙迪亚斑点，并且还固定在至少一只参考一个错字...）

根据您最近的修改，您希望货币和价格都基于相同的条件进行挑选，而原始查询并不明显。每个案件只能评估一个价值，所以你需要重复两个表达式的条件，一个是货币，一个是价格;如果价格为零，您仍然想要更改价格。再次假设where被临时：

select opt.blo, 
    case 
    when opt.notionalcurrency = opt.basecurrency 
     and opt.premiumcurrency = opt.termcurrency 
     then opt.notionalcurrency 
    when opt.notionalcurrency = opt.premiumcurrency 
     then opt.termcurrency 
    else opt.notionalcurrency 
    end as currency, 
    decode (
    case 
     when opt.notionalcurrency = opt.basecurrency 
     and opt.premiumcurrency = opt.termcurrency 
     then opt.termmarketpricepercent/opt.notional 
     when opt.notionalcurrency = opt.premiumcurrency 
     then opt.basemarketprice/100 
     else opt.termmarketpricepercent/100 
    end, 0, 0.000001) as price 
from interface opt; 

价格计算是以前一样，货币表达已经改变以匹配相同的逻辑。尽管如此，您似乎已经丢失了structurename支票。还有一个潜在的假设，即没有一个货币值是空的。

SQL Fiddle部分表和没有数据，只是为了显示查询没有错误。

Answer 2

您错过了最初的case语句中的end。只需将when price = 0 then price = 0.000001

Answer 3

后添加它试试这个：

SELECT opt.blo, 
     CASE 
     WHEN (opt.premiumcurrency IS NOT NULL 
      AND opt.structurename IS NOT NULL) THEN 
      currency = opt.premiumcurrency 
     END, 
     CASE 
     WHEN (opt.notionalcurrency = opt.basecurrency 
      AND opt.premiumcurrency = opt.termcurrency) THEN 
      price = opt.termmarketpricepercent/opt.notional 
     WHEN price = 0 THEN 
      price = 0.000001 
     WHEN opt.premiumcurrency = opt.basecurrency THEN 
      price = opt.basemarketprice/100 
     ELSE 
      price = opt.termmarketpriceprecent/100 
     END 
    FROM interface opt 
WHERE opt.notionalcurrency = opt.basecurrency 
    AND opt.premiumcurrency = opt.termcurrency; 

Answer 4

我对这个查询的几件事情：

1. 按我的理解，选择是你的表的别名，并获得属性你应该写opt.blo而不是blo.opt。
2. Case语句应包含值的情况下，如列名，你正在使用的case语句

我试图修改代码。没有编译，所以可能会出现语法错误。只需检查它。

select opt.blo, 
    case opt.currency 
    when opt.premiumcurrency is not null and opt.structurename is not null 
    then opt.premiumcurrency 
    end as Currency, 
    case opt.price 
    when opt.notionalcurrency = opt.basecurrency and opt.premiumcurrency = opt.termcurrency then opt.termmarketpricepercent/opt.notional 
    when opt.premiumcurrency = opt.basecurrency then opt.basemarketprice /100 
    when price = 0 then price = 0.000001 
    else 
    opt.termmarketpriceprecent /100 
    end as Price, 
FROM interface opt 
WHERE opt.notionalcurrency = opt.basecurrency and opt.premiumcurrency = opt.termcurrency;