如何限制用户需要输入的时间 - Python

Question

编辑： 我通过实现@L3viathan's solution解决了这个问题。这里是更新的代码：

import operator 
import random 
from time import time 
import sys 

def menu(): 
    menu = input("\n\n\n--------\n Menu \n--------\nPress:\n- (1) to play \n- (2) to exit\n: ") 
    if menu == "1": 
     play_game() 
    if menu == "2": 
     print("Exiting...") 
     sys.exit() 
    while menu != "1" or menu != "2": 
     print("Please enter a valid choice") 
     menu = input("--------\n Menu \n--------\nPress:\n- (1) to play \n- (2) to exit\n: ") 
     if menu == "1": 
      play_game() 
     if menu == "2": 
      print("Exiting...") 
      break 

def game_over(): 
    print("Game over.") 
    file = open("score.txt", "r") 
    highscore = file.read() 
    if int(highscore) < score: 
     file = open("score.txt", "w") 
     file.write(score) 
     file.close() 
     print("Score: {}\n\n******************\nNew highscore!\n******************".format(str(score))) 
    else: 
     print("Score: {}\nHighscore: {}".format(str(score), str(highscore))) 

def play_game(): 
    print("Type in the correct answer to the question\nYou have 3 seconds to answer each question\nThe game will continue until you answer a question incorrectly") #displays the welcome message 
    counter = 1 
    score = 0 

    while counter == 1: 
     ops = {"+":operator.add, 
       "-":operator.sub, 
       "x":operator.mul} 
     num1 = random.randint(0, 10) 
     op = random.choice(list(ops.keys())) 
     num2 = random.randint(1, 10) 
     print("\nWhat is {} {} {}? ".format(num1, op, num2)) 
     start = time() 
     guess = float(input("Enter your answer: ")) 
     stop = time() 
     answer = ops.get(op)(num1,num2) 

     if guess == answer: 
      if stop - start > 3: 
       print("You took too long to answer that question. (" + str(stop - start) + " seconds)") 
       def game_over(): 
        print("Game over.") 
        file = open("score.txt", "r") 
        highscore = file.read() 
        if int(highscore) < score: 
         file = open("score.txt", "w") 
         file.write(score) 
         file.close() 
         print("Score: {}\n\n******************\nNew highscore!\n******************".format(str(score))) 
        else: 
         print("Score: {}\nHighscore: {}".format(str(score), str(highscore))) 
        menu() 
       game_over() 
       break 
      else: 
       score = score + 1 
       print("Correct!\nScore: " + str(score)) 
     else: 
      print("Game over.") 
      counter = counter - 1 
      file = open("score.txt", "r") 
      highscore = file.read() 
      if int(highscore) < score: 
       file = open("score.txt", "w") 
       file.write(score) 
       file.close() 
       print("Score: {}\n\n******************\nNew highscore!\n******************".format(str(score))) 
      else: 
       print("Score: {}\nHighscore: {}".format(str(score), str(highscore))) 
     if counter != 1: 
      menu() 
menu() 

谢谢大家的贡献。

------编辑结束-------

我一直在寻找堆栈溢出的解决方案，但是我找不到任何与我的游戏作品，所以我appologise如果这是一个重复的问题。

我正在制作一个数学游戏，用户必须回答一个简单的算术问题，每次用户输入正确的答案时，得分都会增加1。但是，如果用户输入错误的答案，则游戏结束。

我想给游戏添加超时功能，例如，当用户输入其中一个问题的答案时，如果用户超过3秒钟回答，游戏结束。有谁知道如何做到这一点？

我能找到的所有解决方案都是针对Unix的，而不是Windows。

这里是我的代码：

import operator 
import random 

def play_game(): 
    print("Type in the correct answer to the question\nYou have 3 seconds to answer each question\nThe game will continue until you answer a question incorrectly") #displays the welcome message 
    counter = 1 
    score = 0 

    while counter == 1: 
     ops = {"+":operator.add, 
       "-":operator.sub, 
       "x":operator.mul} 
     num1 = random.randint(0, 10) 
     op = random.choice(list(ops.keys())) 
     num2 = random.randint(1, 10) 
     print("\nWhat is {} {} {}? ".format(num1, op, num2)) 
     guess = float(input("Enter your answer: ")) 
     answer = ops.get(op)(num1,num2) 

     if guess == answer: 
      score = score + 1 
      print("Correct!\nScore: " + str(score)) 
     else: 
      print("Game over.") 
      counter = counter - 1 
      file = open("score.txt", "r") 
      highscore = file.read() 
      if int(highscore) < score: 
       file = open("score.txt", "w") 
       file.write(score) 
       file.close() 
       print("Score: {}\n\n******************\nNew highscore!\n******************".format(str(score))) 
      else: 
       print("Score: {}\nHighscore: {}".format(str(score), str(highscore))) 
     if counter != 1: 
      menu = input("\n\n\nMenu\n----\nPress:\n- (1) to play again\n- (2) to exit\n: ") 
      if menu == "1": 
       play_game() 
      elif menu == "2": 
       print("Exiting...") 
       break 
      while menu != "1" or menu != "2": 
       print("Please enter a valid choice") 
       menu = input("Menu\n----\nPress:\n- (1) to play again\n- (2) to exit\n: ") 
       if menu == "1": 
        play_game() 
       elif menu == "2": 
        break 
        print("Exiting...") 
play_game() 

Answer 1

做到这将是一次最简单的方法调用input：

from time import time 

start = time() 
answer = input("Answer this in 3 seconds: 1 + 1 = ") 
stop = time() 

if stop - start < 3: 
    if answer == "2": 
     print("Correct!") 
    else: 
     print("Wrong!") 
else: 
    print("Too slow") 

这种方式很简单，但你不能放弃用户在三秒后输入的能力，只能等待它，然后看看它是否足够快。