SQL查询开始时间

Question

试图找到一个查询来选择数据，将在特定时间08:00开始，直到第二天08:00，我有单独的日期和时间字段，并从日期到日期选择特定的标准。

select * from table 
where datefield between '2014-01-14' and '2014-01-14' 
     and timefield between '08:00' and '08:00' 

Answer 1

不明白为什么datefield和timefield不会被保存在一个datetime -column。 此外，我不知道是什么timefield是的，但如果<和>作品的数据类型，这将工作：

select * from table 
where (datefield = '2014-01-14' and timefield >= '08:00') 
or (datefield = '2014-01-15' and timefield < '08:00') 

编辑：刚刚获悉你可以一起加入date和time领域的一个datetime

select * from table 
where (datefield + timefield) >= '2014-01-11 08:00' 
and (datefield + timefield) < '2014-01-13 08:00' 

Here's the source of adding them together

Answer 2

declare @from datetime = '2014-01-14 08:00' 
declare @to datetime = '2014-01-15 08:00' 
select * from table 
where datefield between cast(@from as date) and @to 
and not(datefield = cast(@from as date) and timefield < cast(@from as time)) 
and not(datefield = cast(@to as date) and timefield > cast(@to as time))