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我对CodeIgniter和PHP一般都很陌生，有两个问题有点相关。在codeigniter的嵌套树中生成适当的路由
我有一个具有无限深度的嵌套类树，可以生成像myapp.com/language和myapp.com/spanish这样的链接，但我希望拥有类似myapp.com/language/spanish的内容。
仅供参考我的模型返回数组像一个数组：
[Languages] => Array ([category_id] => 4 [sub] => Array ([Japanese] => Array ([category_id] => 5) [Spanish] => Array ([category_id] => 6)...
我的辅助函数来创建菜单：
function buildMenu($menu_array, $is_sub=FALSE){
/*
* If the supplied array is part of a sub-menu, add the
* sub-menu class instead of the menu ID for CSS styling
*/
$attr = (!$is_sub) ? ' id="menu"' : ' class="submenu"';
$menu = "<ul$attr>\n"; // Open the menu container
/*
* Loop through the array to extract element values
*/
foreach($menu_array as $id => $properties) {
/*
* Because each page element is another array, we
* need to loop again. This time, we save individual
* array elements as variables, using the array key
* as the variable name.
*/
foreach($properties as $key => $val) {
/*
* If the array element contains another array,
* call the buildMenu() function recursively to
* build the sub-menu and store it in $sub
*/
if(is_array($val))
{
$sub = buildMenu($val, TRUE);
}
/*
* Otherwise, set $sub to NULL and store the
* element's value in a variable
*/
else
{
$sub = NULL;
$$key = $val;
}
}
/*
* If no array element had the key 'url', set the
* $url variable equal to the containing element's ID
*/
if(!isset($url)) {
$url = $id;
}
/*
* Use the created variables to output HTML
*/
$menu .= "<li><a href='$url'>$url</a>$sub</li>\n";
/*
* Destroy the variables to ensure they're reset
* on each iteration
*/
unset($url, $display, $sub);
}
return $menu . "</ul>\n";
这使我对我下一个问题。我如何获得这些链接来调用一个动态函数，该函数可以返回该类别中所有帖子的列表。我在想，如果我能够获得上述路线，我会如何让它们像上面那样，它就像拥有像get_cat_posts($cat_id)这样的功能一样简单。我在这个假设中纠正了吗？是否有多个子级别是一个问题？
对不起，很长的文章。谢谢你的帮助。