我有一个日期数组,我想知道是否有可能搜索一个数组并删除今天的日期之前的任何项目,并保持其余?PHP比较今天日期与(多维)数组中的日期?
这里是我的阵列
Array
(
[0] => Array
(
[date] => 2013-07-14
)
[1] => Array
(
[date] => 2013-08-31
)
[2] => Array
(
[date] => 2013-09-15
)
[3] => Array
(
[date] => 2013-10-12
)
[4] => Array
(
[date] => 2013-10-16
)
[5] => Array
(
[date] => 2013-10-19
)
[6] => Array
(
[date] => 2013-10-23
)
[7] => Array
(
[date] => 2013-10-26
)
[8] => Array
(
[date] => 2013-10-30
)
[9] => Array
(
[date] => 2013-09-07
)
[10] => Array
(
[date] => 2013-08-14
)
[11] => Array
(
[date] => 2013-08-24
)
[12] => Array
(
[date] => 2013-09-11
)
[13] => Array
(
[date] => 2013-09-28
)
[14] => Array
(
[date] => 2013-10-05
)
)
怎么样循环throgh和比较日期与实际所需的数据,并建立一个新的过滤数组? – Fabio
是的,完全有可能使用一些非常简单的技术,其中大多数只涉及一个循环。你有尝试过什么吗?你卡在哪里? – deceze