2009-12-02 37 views

回答

55

像这样:

 var proc = new Process(); 
     proc.StartInfo.FileName = "something.exe"; 
     proc.StartInfo.Arguments = "-v -s -a"; 
     proc.Start(); 
     proc.WaitForExit(); 
     var exitCode = proc.ExitCode; 
     proc.Close(); 
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