我有一个init方法用JSON数据初始化我的模型,但是当我想在NSUserDefaults中存储这个对象时,需要创建acoder和adecoder init方法。用编码器vs Json处理Object init?
即时得到错误:
Cannot invoke 'UserProfileModel.init' with an argument list of type '(apiKey: String, userID: String, userEmail: String, lastName: String, firstName: String, company: String, userImage: String, jobTitle: String)'
为aDecoder初始化为:
required convenience init(coder aDecoder: NSCoder) {
let apiKey = aDecoder.decodeObject(forKey: "apiKey") as! String
let userID = aDecoder.decodeObject(forKey: "userID") as! String
let userEmail = aDecoder.decodeObject(forKey: "userEmail") as! String
let lastName = aDecoder.decodeObject(forKey: "lastName") as! String
let firstName = aDecoder.decodeObject(forKey: "firstName") as! String
let company = aDecoder.decodeObject(forKey: "company") as! String
let userImage = aDecoder.decodeObject(forKey: "userImage") as! String
let jobTitle = aDecoder.decodeObject(forKey: "jobTitle") as! String
self.init(apiKey: apiKey, userID: userID, userEmail: userEmail, lastName: lastName, firstName: firstName, company: company, userImage: userImage, jobTitle: jobTitle)
}
,但我已经有这个初始化:
init?(_ json: JSON) {
// Map API Key from top level
guard let apiKey = json["apikey"].string
else { return nil }
// assign user
guard let userID = json["user"]["id"].string,
let userEmail = json["user"]["email"].string,
let lastName = json["user"]["lastname"].string,
let firstName = json["user"]["firstname"].string
else { return nil }
// assign optionals to user
let company = json["user"]["company"].string
let userImage = json["user"]["image"].string
let jobTitle = json["user"]["jobtitle"].string
// Assign to model properties
self.apiKey = apiKey
self.userID = userID
self.userEmail = userEmail
self.lastName = lastName
self.firstName = firstName
self.company = company
self.userImage = userImage
self.jobTitle = jobTitle
}
如何兼顾双方无劳动抛出这个错误?
如果我使它成为必需,我如何用JSON初始化?生病也需要这样做? – jackdm
@jackdm:请阅读我更新的答案我已经指定了为什么你不需要self.init –
@jackdm:请阅读更新的答案。如果有任何混淆,请让我知道 –