2015-11-13 43 views
1

我正在拼命用我的多维数组。我实际上已经完成了几个小时的研究,但找不到任何有用的东西。推多维数组

我有一个多维数组,看起来像这样:

var locations = [ 
    ['Bondi Beach', -33.890542, 151.274856, 4, 0], 
    ['Coogee Beach', -33.923036, 151.259052, 1, 1], 
    ['Cronulla Beach', -34.028249, 151.157507, 3, 2], 
    ['Manly Beach', -33.80010128657071, 151.28747820854187, 2, 0], 
    ['Maroubra Beach', -33.950198, 151.259302, 5, 2] 
]; 

现在我想要的东西添加到阵列推,如:


locations.push(DATA HERE); // 'Cronulla Beach 2', -34.028249, 151.157507, 8, 7 

应该看哪个像这在最后:

var locations = [ 
    ['Bondi Beach', -33.890542, 151.274856, 4, 0], 
    ['Coogee Beach', -33.923036, 151.259052, 1, 1], 
    ['Cronulla Beach', -34.028249, 151.157507, 3, 2], 
    ['Manly Beach', -33.80010128657071, 151.28747820854187, 2, 0], 
    ['Maroubra Beach', -33.950198, 151.259302, 5, 2], 
    ['Cronulla Beach 2', -34.028249, 151.157507, 8, 7] 
]; 

注意:我需要一个数组,因此如果它是一个对象的解决方案,它不会帮助我。

最好的解决方案还应该工作,如果阵列仍然是空喜欢locations[];

回答

1

只要把合作在另一个阵列中,并将其推入locations阵列,如

locations.push(['Cronulla Beach 2', -34.028249, 151.157507, 8, 7]); 
2

由于多维数组只是数组的数组,你可以通过只配售对象的方括号中列表中创建一个新的数组,你可以这样做:

locations.push(['Cronulla Beach 2', -34.028249, 151.157507, 8, 7]); 

要访问或修改现有的位置,使用其指数:

var location = locations[0]; 
console.log(location); 
locations[0][0] = "Bomba Beach"; // change name of first location 
locations[0][1] = -30.2; // change latitude of first location