哪里有IN运营商，但开始 - 而不是完全匹配

Question

我有一个表的情况。

[ I D ] [ n a m e ] [ 2 ID] 
310000 Kikiriki 100001 
310010 Mandalina 100002 
210000 Keyboard 200001 
310020 Maouse  100003 
012001 PC   NULL 

随着SELECT * FROM Table WHERE [2 ID] IN ('310000','012001')我只得到从310000和012001.我需要与310％或012％启动所有ID的结果的结果。

AND Mat_FinDok_KontoPr2 like '310%' 
AND Mat_FinDok_KontoPr2 like '012%' 
AND Mat_FinDok_Dobavuvac LIKE '%' 
AND Mat_FinDok_TipDok LIKE '000005%' 
AND Mat_FinDok_DataDok BETWEEN '2014-01-01' AND '2014-12-31' 

Result 0 Rows 

以及与此

AND mat_findok.Mat_FinDok_KontoPr2 IN ('310000', '012001') 
AND mat_findok.Mat_FinDok_Dobavuvac LIKE '%' 
AND Mat_FinDok_Dobavuvac LIKE '%' 
AND Mat_FinDok_TipDok LIKE '000005%' 
AND Mat_FinDok_DataDok BETWEEN '2014-01-01' AND '2014-12-31' 

Result 11 Rows 

但在这里我不从012002有结果。

Answer 1

那么你应该写查询以获得想要的东西：

SELECT * 
FROM Table 
WHERE id like '310%' or id like '012%'; 

Answer 2

使用LIKE与%通配符：

SELECT * FROM MyTable WHERE Id LIKE '310%' OR Id LIKE '012%' 

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