2016-09-01 161 views
3

我有一个表格字段写入功能,Odoo:在Odoo 8

Name : 
First Name: 
Second Name: 
Last Name: 

我已经写了创建功能,当我们进入第一个名字,第二个名字,姓氏,它将设置名称

First Name: Test First 
Second Name: Test Second 
Last Name: Test Third 

就会产生

Name : Test First Test Second Test Third 

这是因为创建乐趣ction。

@api.model 
def create(self, vals): 
    child = vals.get('child_first_name') 
    child_middle = vals.get('child_middle_name') or ' ' 
    child_last = vals.get('child_last_name') or ' ' 
    if child: 
     vals['name'] = self.env['ir.sequence'].next_by_code('application_form') 
     vals['child_name'] = child + ' ' + child_middle + ' ' + child_last 
    return super(application_form, self).create(vals) 

当我修改任何这些字段

First Name 
Second Name 
Last Name 

的应再次设置的名称。

请建议一个功能有很好的方法。

以同样的方式:

问题2:

有一个布尔字段。

对于参考:

我已经写在要生成的序列号创建方法。 如果我取消选中布尔字段,则要生成其他一组序列号。

请建议功能。

写作的上述问题

@api.multi 
def write(self, vals): 
    application = self.browse(self.id) 
    if vals.has_key('child_first_name'): 
     fname = vals.get('child_first_name') or ' ' 
    else : 
     fname = application.child_first_name 
    if vals.has_key('child_middle_name'): 
     mname = vals.get('child_middle_name') or ' ' 
    else : 
     mname = application.child_middle_name 
    if vals.has_key('child_last_name'): 
     lname = vals.get('child_last_name') or ' ' 
    else : 
     lname = application.child_last_name 
    full_name = fname + ' ' + mname + ' ' + lname 
    vals.update({'child_name':full_name}) 
    return super(application_form, self).write(vals) 
+0

感谢您的编辑 –

回答

1

这里是你如何能做到的例子这

@api.multi 
def write(self, vals): 
    # checks that new field value 
    # is not equal to old one 
    def _is_changed(name): 
     return name in vals and self[name] != vals[name] 

    # returns new field value if present 
    # otherwise return old value if present 
    # else return default value 
    def _get_field(name, default=''): 
     return vals.get(name, self[name]) or default 

    # choose which sequence to use based on boolean seq_flag 
    seq = 'some_seq' if _get_field('seq_flag', False) else 'application_form' 

    # if one of name parts was changed 
    if _is_changed('child_first_name') or \ 
     _is_changed('child_middle_name') or \ 
     _is_changed('child_last_name'): 
     vals['name'] = self.env['ir.sequence'].next_by_code(seq) 
     name_parts = [ 
      _get_field('child_first'), 
      _get_field('child_middle_name'), 
      _get_field('child_last_name') 
     ] 
     # write only non-empty name parts 
     vals['child_name'] = " ".join([_ for _ in name_parts if _]) 
    return super(application_form, self).write(vals) 

您也可以使用计算child_last_name场和@api.depends解决你的问题

的第一部分
child_name = fields.Char(compute='_compute_name') 

@api.one 
@api.depends('child_first', 'child_middle_name', 'child_last_name') 
def _compute_upper(self): 
    name_parts = [ 
     self.child_first, 
     self.child_middle_name, 
     self.child_last_name 
    ] 
    self.child_name = " ".join([_ for _ in name_parts if _]) 
+0

Tha nks vsminkov。我有一个布尔型的字段**示例:参考**。当我检查布尔型字段序列号将为AM/001,并且当我取消选中布尔型字段时,序列号将为ORD/001。假定序列号被创建为ORD/001,我要去编辑那个布尔字段,那么它应该是AM/001。它应该只改变一次。因为每次我以这种形式编辑其他字段,sequnce也会增加 –