你并不需要一个可变参数模板:
#include <algorithm>
#include <iostream>
#include <iterator>
namespace Detail {
template <typename Functor, typename List>
typename Functor::result_type reduce(Functor f, const List& list) {
using std::begin;
using std::end;
typename Functor::result_type result{};
auto pos = begin(list);
if(pos != end(list)) {
result = *pos;
while(++pos != end(list))
result = f(result, *pos);
}
return result;
}
} // namespace Detail
template <typename Functor, typename List>
typename Functor::result_type reduce(Functor f, const List& list) {
return Detail::reduce(f, list);
}
template <typename Functor, typename T>
typename Functor::result_type reduce(Functor f, std::initializer_list<T> list) {
return Detail::reduce(f, list);
}
int main() {
std::cout << reduce(std::plus<int>(), {1, 2, 3, 4, 5, 6, 7}) << std::endl;
const int input[3] = {1, 2, 3};
std::cout << reduce(std::plus<int>(), input) << std::endl;
}
012使用 'constexpr'
A C++ 11(克++ 4.8.4)的变化:
#include <algorithm>
#include <iostream>
#include <iterator>
// constexpr plus is C++14
template<typename T>
struct plus : public std::binary_function<T, T, T>
{
constexpr T operator()(const T& x, const T& y) const { return x + y; }
};
// constexpr begin is C++14
template<class T, std::size_t N>
inline constexpr T* begin(T (&array)[N]) { return array; }
// constexpr end is C++14
template<class T, std::size_t N>
inline constexpr T* end(T (&array)[N]) { return array + N; }
template <typename Functor, typename Iterator>
inline constexpr typename Functor::result_type
reduce(
const Functor& f,
const typename Functor::result_type& value,
Iterator first,
Iterator last)
{
return (first != last)
? reduce(f, f(value, *first), first + 1, last)
: value;
}
template <typename Functor, typename T, std::size_t N>
constexpr typename Functor::result_type reduce(const Functor& f, T (&array)[N]) {
// constexpr begin/end is C++14
// using std::begin;
// using std::end;
return reduce(f, typename Functor::result_type{}, begin(array), end(array));
}
template <typename Functor, typename T>
inline constexpr typename Functor::result_type reduce(
const Functor& f,
std::initializer_list<T> list)
{
return reduce(f, typename Functor::result_type{}, list.begin(), list.end());
}
int main() {
static constexpr int input[3] = {1, 2, 3};
static_assert(28 == reduce(plus<int>(), {1, 2, 3, 4, 5, 6, 7}), "Failure");
static_assert(6 == reduce(plus<int>(), input), "Failure");
}
是什么问题?只需添加一个超载需要'std :: initializer_list'? –
为什么不使用'std :: accumulate'? –
@ Cheersandhth.-Alf:编译时间 –