我有下面的代码从文件读取数据并将其存储在一个字符串变量,现在当我运行它,它给了我一个字符串越界异常。我该如何解决这个错误?为什么我得到一个字符串越界异常
运行命令和错误:
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 1882
at java.lang.String.charAt(String.java:694)
at IfCounter2.main(IfCounter2.java:92)
代码:
import java.io.*;
public class IfCounter2
{
// method to check if there is a single-line comment
public static boolean lineAComment(String line)
{
if (line.contains("//"))
return true;
return false;
}
// method to check if there is a multi-line comment start
public static boolean multiLineCommentStart(String line)
{
if (line.contains("/*"))
return true;
return false;
}
// method to check if there is a multi-line comment end
public static boolean multiLineCommentEnd(String line)
{
if (line.contains("*/"))
return true;
return false;
}
public static void main(String[] args) throws IOException
{
// variable to keep track of ifs
int ifCount = 0;
// check how many arguments are passed
int numArgs = args.length;
// look at all the arguments
// they don't want to count ifs in comments ************************************ --nocomment was entered
if (args[0].equals("--nocomments"))
{
// create a new BufferReader for the file that will be at args 1
BufferedReader reader = new BufferedReader(new FileReader (args[1]));
String line = null;
StringBuilder stringBuilder = new StringBuilder();
String ls = System.getProperty("line.separator");
// read from the text file
boolean multiLineComment = true;
// ignore comments as we store data in a String variable
while ((line = reader.readLine()) != null)
{
if (!multiLineCommentStart(line))
{
multiLineComment = true;
} // end if
if (multiLineComment)
{
if (!multiLineCommentEnd(line))
{
multiLineComment = false;
} // end if
} // end if
if (!lineAComment(line) && !multiLineComment)
{
stringBuilder.append(line);
stringBuilder.append(ls);
} // end if
} // end while
// create a new string with stringBuilder data
String tempString = stringBuilder.toString();
System.out.println(tempString);
// create one last string to look for our valid if(s) in,
// with ALL whitespace removed
String compareString = tempString.replaceAll("\\s","");
//System.out.println(compareString);
for (int i = 0; i < compareString.length(); i++)
{
if (compareString.charAt(i) == ';' || compareString.charAt(i) == '}' || compareString.charAt(i) == '{' || compareString.charAt(i) == '\n')
{
i++;
if (compareString.charAt(i) == 'i')
{
i++;
if (compareString.charAt(i) == 'f')
{
i++;
if (compareString.charAt(i) == '(')
ifCount++;
} // end if
} // end if
} // end if
} // end for
} // end if (comments option)
// else ******************************************************** count ifs as usual
/*else
{
for (int c = 0; c <= numArgs; c++)
{
// create a new BufferReader
BufferedReader reader2 = new BufferedReader(new FileReader (args[c]));
String line2 = null;
StringBuilder stringBuilder2 = new StringBuilder();
String ls2 = System.getProperty("line.separator");
// read from the text file
while ((line2 = reader2.readLine()) != null)
{
stringBuilder2.append(line2);
stringBuilder2.append(ls2);
}
// create a new string with stringBuilder data
String tempString2 = stringBuilder2.toString();
// create one last string to look for our valid if(s) in
// with ALL whitespace removed
String compareString2 = tempString2.replaceAll("\\s","");
// check for valid if(s)
for (int i = 0; i < compareString2.length(); i++)
{
if (compareString2.charAt(i) == ';' || compareString2.charAt(i) == '}' || compareString2.charAt(i) == '{') // added opening "{" for nested ifs :)
{
i++;
if (compareString2.charAt(i) == 'i')
{
i++;
if (compareString2.charAt(i) == 'f')
{
i++;
if (compareString2.charAt(i) == '(')
ifCount++;
} // end if
} // end if
} // end if
} // end for
} // end if (else option)
} // end for
*/
// print the number of valid "if(s) with a new line after"
System.out.println(ifCount + "\n");
}
}
您是否尝试过使用调试器并在第92行设置断点?从那里,你可以检查变量并精确确定为什么传递给'charAt'的索引是无效的。 –
什么行代码在92行? –
我不确定这段代码的目的是什么,但显然是不正确的。如果它应该解析Java代码..所以你不能识别是(true); (假);在一行中作为两个ifs;)你将只计算一个。 –