使用COUNT（id）作为条件的条件SELECT COUNT（id）？

Question

我想只选择类别ID，其中分配给该类别的文章数量超过3个。

我已经尝试了各种排列并发布了下面的一个，我觉得最清楚的解释了我在尝试尽管我有一种感觉，我需要使用嵌套的SELECT。我试过嵌套的SELECTs，但没有成功。

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles GROUP BY categoryID WHERE numArticles > 3 

Answer 1

使用having

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles GROUP BY categoryID HAVING COUNT(articleID) > 3 

Answer 2

改为使用HAVING。

http://techonthenet.com/sql/having.php

Answer 3

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles GROUP BY categoryID 
HAVING COUNT(articleID) > 3 

Answer 4

您需要使用Having条款

Select CategoryId, Count(ArticleId) as numArticles 
From dbo.Articles 
Group By CategoryId 
Having Count(ArticleId) > 3 

Answer 5

使用HAVING条款：

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles 
GROUP BY categoryID 
HAVING COUNT(articleID) > 3 

从MSDN：

指定组或聚合的搜索条件。 HAVING只能用于SELECT语句。 HAVING通常用在GROUP BY子句中。当不使用GROUP BY时，HAVING的行为如同WHERE子句。

Answer 6

对于这个不使用WHERE，你必须使用HAVING来代替。

试试这个：

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles GROUP BY categoryID HAVING numArticles > 3