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我有一个c#gui,当点击一个按钮时调用引用的C++ dll。在C++ DLL我有以下代码Winsock连接失败,错误10049
SOCKADDR_IN server;
server.sin_port=htons (54321);
server.sin_family = AF_INET;
server.sin_addr.s_addr = INADDR_ANY;
// Connect to server.
int iResult = connect(Socket, (SOCKADDR *) & server, sizeof (server));
if (iResult == SOCKET_ERROR) {
long iError = WSAGetLastError();
if (iError == WSAEWOULDBLOCK)
printf("recv failed with error: WSAEWOULDBLOCK\n");
else
printf("recv failed with error: %ld\n", iError);
wprintf(L"connect function failed with error: %ld\n", WSAGetLastError());
iResult = closesocket(Socket);
if (iResult == SOCKET_ERROR)
wprintf(L"closesocket function failed with error: %ld\n", WSAGetLastError());
WSACleanup();
return 1;
}
在C#调用程序的DLL调用和连接通过Winsock2的在DLL中做之前,我有
再经过IPAddress localAddr = IPAddress.Parse("127.0.0.1");
TcpListener serverSocket = new TcpListener(localAddr,54321);
int requestCount = 0;
TcpClient clientSocket = default(TcpClient);
serverSocket.Start();
的dll是叫我做
//调用DLL运行连接代码
clientSocket = serverSocket.AcceptTcpClient();//hangs up here because dll can't Connect.
在C当我一步++ DLL在连接我得到错误10049,这是 WSAEADDRNOTAVAIL。
什么我在连接做错了电话?在msdn示例之后,我选择了54321作为端口。 谢谢!
的感谢!这让事情奏效!非常感激! – user2192008