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我正在从Twitter API中获取数据。将数据从JSON对象转换为数据框并加载到数据仓库。查找下面的输入和代码片段。将嵌套的JSON对象转换为R中的数据帧
我对R编程非常陌生。
stats_campaign.data <- content(stats_campaign.request)
print(stats_campaign.data)
O/P：
`{
"data_type": [ "stats" ],
"time_series_length": [ 1 ],
"data": [
{
"id": [ "XXXXX" ],
"id_data": [
{
"segment": {},
"metrics": {
"impressions": {},
"tweets_send": {},
"qualified_impressions": {},
"follows": {},
"app_clicks": {},
"retweets": {},
"likes": {},
"engagements": {},
"clicks": {},
"card_engagements": {},
"replies": {},
"url_clicks": {},
"carousel_swipes": {}
}
}
]
},
{
"id": [ "XXXX1" ],
"id_data": [
{
"segment": {},
"metrics": {
"impressions": {},
"tweets_send": {},
"qualified_impressions": {},
"follows": {},
"app_clicks": {},
"retweets": {},
"likes": {},
"engagements": {},
"clicks": {},
"card_engagements": {},
"replies": {},
"url_clicks": {},
"carousel_swipes": {}
}
}
]
},`
当我读这个JSON值，
stats_json_file <- sprintf("P:/R Repos/R
Applications/TwitterAPIData/stats_test_data-%s.json", TODAY)
jsonlite::fromJSON(stats_json_file)
**Result :**
id id_data
1 5wcaz NULL
2 5ub2u NULL
3 5wb8x NULL
4 5wb1j NULL
5 5yqwj NULL
6 5pq5i NULL
7 5u197 NULL
8 5z2js NULL
9 6fqh0 333250, 4, 9, 19, 111, 3189, 3156, 5, 1091
10 5tvr1 NULL
11 5yqw4 NULL
12 5qqps NULL
13 5yqvw NULL
14 5ygom NULL
15 5nc88 NULL
16 5yg94 NULL
17 65t9e NULL
18 5peck NULL
19 63pg1 247283, 17, 22, 35, 297, 5514, 5450, 6, 2971
20 6cdvy 156705, 1, 2, 6, 112, 10933, 605, 170
From my JSON file I want Id and whole "metrics": {
"impressions": {},
"tweets_send": {},
"qualified_impressions": {},
"follows": {},
"app_clicks": {},
"retweets": {},
"likes": {},
"engagements": {},
"clicks": {},
"card_engagements": {},
"replies": {},
"url_clicks": {},
"carousel_swipes": {}
}
and convert to Data Frame to load into Data Base. Plzz Help..!
我如何解析这个JSON对象。我想检索整个Metrics对象的Id &。然后想要转换成数据框以加载到SQL表中。
读书，我用下面的代码的多个标识的&指标值，
`test <- list()
for(i in 1:len)
{ test <- unlist(stats_campaign.data$data[[i]])
print(test)}`
**Output:**
id
"5wcaz"
id
"5ub2u"
id
"5wb8x"
id
"5wb1j"
id
"5yqwj"
id
"5pq5i"
id
"5u197"
id
"5z2js"
id
"5tvr1"
id
"5yqw4"
id
"5qqps"
id
"5yqvw"
id
"5ygom"
id
"5nc88"
id
"5yg94"
id
"65t9e"
id
"5peck"
id id_data.metrics.impressions
"63pg1" "133227"
id_data.metrics.tweets_send id_data.metrics.follows
"10" "9"
id_data.metrics.retweets id_data.metrics.likes
"17" "96"
id_data.metrics.engagements id_data.metrics.clicks
"2165" "2134"
id_data.metrics.replies id_data.metrics.url_clicks
"5" "1204"
id id_data.metrics.impressions
"6cdvy" "176164"
id_data.metrics.tweets_send id_data.metrics.retweets
"2" "10"
id_data.metrics.likes id_data.metrics.engagements
"121" "9708"
id_data.metrics.clicks id_data.metrics.url_clicks
"620" "160"
在一个为我所用列表或别的东西每次追加的价值，我怎么能做到这一点..？ ？我正在使用正确的方法吗？有没有其他方法可以解析嵌套的JSON对象，并直接放入数据框..？
请帮助..！提前致谢..！
如果您的JSON在语法上有效，那么在R中，您可以执行'jsonlite :: fromJSON（your_text）'。不过，你的括号似乎有一些问题。 – Gregor
这是我的JOSN FOrmat， –
好的，你的JSON现在是有效的。你可以在其上运行'jsonlite :: fromJSON（your_text）'并获得有用的结果。你想要什么？而不是显示你*不需要的输出，你能显示你想要的输出吗？ – Gregor