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SELECT
`wp_posts`.`post_title`
, `wp_posts`.`post_content`
, `wp_posts`.`post_type`
, `wp_posts`.`ID`
, `wp_posts`.`post_date`
, `wp_usermeta`.`user_id` AS `userID`
, `wp_usermeta`.`meta_value` AS `city`
, `wp_usermeta`.`meta_value` AS `state`
, `wp_users`.`fbconnect_userid` AS `fbuid`
FROM `wp_posts`
INNER JOIN `wp_emu_shop_reviews`
ON (`wp_posts`.`ID` = `wp_emu_shop_reviews`.`postID`)
LEFT JOIN `wp_users`
ON (`wp_emu_shop_reviews`.`wpUserID` = `wp_users`.`ID`)
LEFT JOIN `wp_usermeta`
ON (`wp_users`.`ID` = `wp_usermeta`.`user_id` AND `wp_usermeta`.`meta_key` ='location_city')
OR(`wp_users`.`ID` = `wp_usermeta`.`user_id` AND `wp_usermeta`.`meta_key` ='location_state')
WHERE (`wp_posts`.`post_type` = "review"
AND `wp_posts`.`post_status` = "publish");
这不起作用的部分是将城市和州纳入结果中。当前查询将该城市列入城市和州列。 Obv,最后一次加入是问题所在。每个表格有2个值的连接AS别名值
"This is the title" "blahblahblah" "review" "2074" "2012-05-03 00:03:10" "15" "Redmond" "Redmond" "xxxxxxxx"
我probly需要得到更多的价值出来的wp_usermeta表,但我敢肯定,如果有人soves这个问题对我来说我自己看着办吧。
啊..根据Juris Malinens和Explosion Pills的建议,我得到了这个查询的工作,我想。
SELECT
`wp_posts`.`post_title`
/* , `wp_posts`.`post_content` */
, `wp_posts`.`post_type`
, `wp_posts`.`ID`
, `wp_posts`.`post_date`
/* , `wp_usermeta`.`user_id` AS `userID` */
, um1.user_id AS `userID`
, um1.meta_value AS `city`
, um2.meta_value AS `state`
, `wp_users`.`fbconnect_userid` AS `fbuid`
FROM `wp_posts`
INNER JOIN `wp_emu_shop_reviews`
ON (`wp_posts`.`ID` = `wp_emu_shop_reviews`.`postID`)
LEFT JOIN `wp_users`
ON (`wp_emu_shop_reviews`.`wpUserID` = `wp_users`.`ID`)
/* LEFT JOIN `wp_usermeta`
ON (`wp_users`.`ID` = `wp_usermeta`.`user_id` AND `wp_usermeta`.`meta_key` ='location_city') */
LEFT JOIN wp_usermeta um1 ON (`wp_users`.`ID` = `um1`.`user_id` AND um1.meta_key ='location_city')
LEFT JOIN wp_usermeta um2 ON(`wp_users`.`ID` = `um2`.`user_id` AND um2.meta_key ='location_state')
WHERE (`wp_posts`.`post_type` = "review"
AND `wp_posts`.`post_status` = "publish");
怎么样:LEFT JOIN'wp_usermeta' usermeta1 ON('wp_users'.'ID' ='wp_usermeta'.'user_id'和'wp_usermeta'.'meta_key' = 'location_city')LEFT JOIN'ON wp_usermeta' usermeta2 ('wp_users'.'ID' ='wp_usermeta'.'user_id' AND'wp_usermeta'.'meta_key' ='location_state')? – 2013-03-21 14:53:45