从联系人列表中获取电子邮件地址Android

Question

我只想显示其电子邮件地址存在的联系人姓名。否则，该联系人姓名不应显示在列表中。我怎样才能做到这一点？任何人都可以帮我吗？

Answer 1

public ArrayList<String> getNameEmailDetails(){ 
     ArrayList<String> names = new ArrayList<String>(); 
     ContentResolver cr = getContentResolver(); 
     Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null); 
     if (cur.getCount() > 0) { 
      while (cur.moveToNext()) { 
       String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID)); 
       Cursor cur1 = cr.query( 
         ContactsContract.CommonDataKinds.Email.CONTENT_URI, null, 
         ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?", 
           new String[]{id}, null); 
       while (cur1.moveToNext()) { 
        //to get the contact names 
        String name=cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)); 
        Log.e("Name :", name); 
        String email = cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA)); 
        Log.e("Email", email); 
        if(email!=null){ 
         names.add(name); 
        } 
       } 
       cur1.close(); 
      } 
     } 
     return names; 
    } 

上述方法返回具有电子邮件ID的名称的数组列表。

Answer 2

如果您已经可以获取联系人及其电子邮件地址（如果存在），为什么不从联系人列表中删除没有电子邮件地址的联系人？

有关Android Contacts API的更多信息，请参阅here。

Answer 3

if (cur.getCount() > 0) { 
      while (cur.moveToNext()) { 
       String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID)); 
       String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)); 

       Cursor emailCur = getContentResolver().query(ContactsContract.CommonDataKinds.Email.CONTENT_URI,null,ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?", new String[]{id},null); 
       while (emailCur.moveToNext()) { 
         String email = emailCur.getString(emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA)); 
         Log.e("Email",name+" "+email); 
        } 
        emailCur.close(); 
       } 

      } 

Answer 4

这是我的超级快速查询拉电子邮件地址。这是不是拉的所有联系列由其他答案的建议快得多......

public ArrayList<String> getNameEmailDetails() { 
    ArrayList<String> emlRecs = new ArrayList<String>(); 
    HashSet<String> emlRecsHS = new HashSet<String>(); 
    Context context = getActivity(); 
    ContentResolver cr = context.getContentResolver(); 
    String[] PROJECTION = new String[] { ContactsContract.RawContacts._ID, 
      ContactsContract.Contacts.DISPLAY_NAME, 
      ContactsContract.Contacts.PHOTO_ID, 
      ContactsContract.CommonDataKinds.Email.DATA, 
      ContactsContract.CommonDataKinds.Photo.CONTACT_ID }; 
    String order = "CASE WHEN " 
      + ContactsContract.Contacts.DISPLAY_NAME 
      + " NOT LIKE '%@%' THEN 1 ELSE 2 END, " 
      + ContactsContract.Contacts.DISPLAY_NAME 
      + ", " 
      + ContactsContract.CommonDataKinds.Email.DATA 
      + " COLLATE NOCASE"; 
    String filter = ContactsContract.CommonDataKinds.Email.DATA + " NOT LIKE ''"; 
    Cursor cur = cr.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, PROJECTION, filter, null, order); 
    if (cur.moveToFirst()) { 
     do { 
      // names comes in hand sometimes 
      String name = cur.getString(1); 
      String emlAddr = cur.getString(3); 

      // keep unique only 
      if (emlRecsHS.add(emlAddr.toLowerCase())) { 
       emlRecs.add(emlAddr); 
      } 
     } while (cur.moveToNext()); 
    } 

    cur.close(); 
    return emlRecs; 
} 

我试图通过“阿加瓦尔香卡”提供的代码，但它花了约4秒，让我在测试设备上的接触，这代码耗时约0.04秒。这个更快的代码我加入了SaluSafe应用程序。 Download SaluSafe from google play。

Answer 5

以下是从联系人列表中获取联系人的电子邮件ID的简单方法。你需要传递的用户接触ID下面的方法，如果存在

public String getEmail(String contactId) { 
    String emailStr = ""; 
    final String[] projection = new String[]{ContactsContract.CommonDataKinds.Email.DATA, 
      ContactsContract.CommonDataKinds.Email.TYPE}; 

    Cursor emailq = managedQuery(ContactsContract.CommonDataKinds.Email.CONTENT_URI, projection, ContactsContract.Data.CONTACT_ID + "=?", new String[]{contactId}, null); 

    if (emailq.moveToFirst()) { 
     final int contactEmailColumnIndex = emailq.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA); 

     while (!emailq.isAfterLast()) { 
      emailStr = emailStr + emailq.getString(contactEmailColumnIndex) + ";"; 
      emailq.moveToNext(); 
     } 
    } 
    return emailStr; 
} 

如果您想了解如何在您的应用程序获取联系人列表请点击此链接也将返回你的电子邮件ID：show contact list in app android - trinitytuts

Answer 6

另一种解决方案。

private static final Uri URI_CONTACT_DATA = ContactsContract.Data.CONTENT_URI; 
private static final String COLUMN_EMAIL = ContactsContract.CommonDataKinds.Email.ADDRESS; 
private static final String COLUMN_DISPLAY_NAME = ContactsContract.Contacts.DISPLAY_NAME_PRIMARY; 
private static final String COLUMN_MIMETYPE = ContactsContract.Data.MIMETYPE; 

private static final String[] PROJECTION = { 
     COLUMN_DISPLAY_NAME, 
     COLUMN_EMAIL, 
     COLUMN_MIMETYPE 
}; 

private Cursor getCursor() { 
    ContentResolver resolver = context.getContentResolver(); 
    String selection = COLUMN_MIMETYPE + "=?"; 
    final String[] selectionArgs = {ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE}; 
    return resolver.query(URI_CONTACT_DATA, PROJECTION, selection, selectionArgs, null); 
} 

的问题是，在ContactsContract.Contacts.CONTENT_URI表所拥有的整个联系人数据库。这包括电话号码，电子邮件，组织，甚至是完全自定义的数据，所以如果不使用ContactsContract.Data.MIMETYPE进行筛选，就不能使用它。此数据库中的一行包含与某个帐户相关的值（或值，它具有15个通用列），因此您可能需要自己对它们进行分组。我需要这个来自动完成电子邮件，所以格式（每行电子邮件）是完美的。