Python通过目录递归

Question

我正在尝试使用os.walk（）来浏览目录。我目前的执行情况如下：

print(".:") 
for dirname, dirnames, filenames in os.walk(path): 
    for filename in filenames: 
     print(os.path.join(dirname, filename)) 
    print() 
    for subdirname in dirnames: 
     print(os.path.join(dirname, subdirname) + ":") 

对于 “路径” 我得到以下输出：

.: 
./File5.py 
./File 3.py 
./File 1.py 

./directory 2: 
./directory 4: 
./Test Directory: 
./directory 2/player_career.csv 
./directory 2/File2.py 

./directory 4/test.txt 
./directory 4/Homework4.py 

./directory 4/__pycache__: 
./directory 4/__pycache__/File4.cpython-32.pyc 


./Test Directory/Test 3: 
./Test Directory/Test 2: 
./Test Directory/Test 3/ttt 

./Test Directory/Test 2/Untitled Document 2 
./Test Directory/Test 2/Untitled Document 

./Test Directory/Test 2/Untitled Folder: 
./Test Directory/Test 2/Untitled Folder/jjj 

，我期待的输出为：

.: 
./File5.py 
./File 3.py 
./File 1.py 

./directory 2: 

./directory 2/player_career.csv 
./directory 2/File2.py 

./directory 4: 

./directory 4/test.txt 
./directory 4/Homework4.py 

./directory 4/__pycache__: 

./directory 4/__pycache__/File4.cpython-32.pyc 

./Test Directory: 

./Test Directory/Test 2: 

./Test Directory/Test 2/Untitled Document 
./Test Directory/Test 2/Untitled Document 2 

./Test Directory/Test 2/Untitled Folder: 

./Test Directory/Test 2/Untitled Folder/jjj 

./Test Directory/Test 3: 

./Test Directory/Test 3/ttt 

如果我这样做是递归的，我可以简单地调用我找到的每个子目录的函数，但是我很难找出使用os.walk（）这样做的优雅方法。

我的问题：我如何使用os.walk（）

Answer 1

不要立即打印出子目录，而是打印出来，当你在目录实际上是得到上面的输出。

一个例子：

for dirname, dirnames, filenames in os.walk(path): 
    print() 
    print(dirname + ":") 
    for filename in filenames: 
     print(os.path.join(dirname, filename)) 

的方式os.walk作品，试图打印所有的目录名立即在你让他们在dirnames的时间不会给你想要的顺序。