我有以下的PHP服务器代码:PHP SOAP服务器返回的XML用没有标签
$xml ="<?xml version=\"1.0\" encoding=\"UTF-8\"?>";
$root = "Data";
$warmdata = "WarmData";
$brinedata = "BrineData";
$permindata = "PerMinData";
$xml .= "<$root>";
$xml .= "<$warmdata>";
foreach($result as $row)
{
$xml .= "<WarmIn>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmIn>";
}
foreach($result2 as $row)
{
$xml .= "<WarmOut>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmOut>";
}
$xml .= "</$warmdata>";
$xml .= "<$brinedata>";
foreach($result3 as $row)
{
$xml .= "<BrineIn>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrineIn>";
}
foreach($result4 as $row)
{
$xml .= "<BrineOut>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrineOut>";
}
$xml .= "</$brinedata>";
$xml .= "<$permindata>";
foreach($result5 as $row)
{
$xml .= "<WarmPerMin>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmPerMin>";
}
foreach($result6 as $row)
{
$xml .= "<BrinePerMin>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrinePerMin>";
}
$xml .= "</$permindata>";
$xml .= "</$root>";
header ("Content-Type:text/xml");
return $xml;
$options=array('uri'=>'http://localhost/');
$server = new SoapServer(NULL,$options);
$server->setClass('DBData');
$server->handle();
我试图让使用SOAP客户端正确格式化XML输出,但是当我请求的XML,该出只包含从单个数据库中检索的数字,没有实际的xml标记。 我该如何修改它,以便在输出中使用标签?
这是功能?如果没有返回将终止执行 – RiggsFolly
@RiggsFolly是的,它是一个函数。它的工作原理,只有输出缺少所有xml标签,而是显示在一行中。 – kisbovan93
那么请显示所有相关的代码。我们只能调试我们所看到的**,我们不是千里眼的** – RiggsFolly