我需要检查清单,清单包含到指定列表类似值列表,值可在不同的顺序,但如果所有的值都是相同的,它应该返回真列表与另一个列表列表比较
a= ["1","2","3","4","5"]
b= ["2","3","6","4","7"]
e = (["1","3","2","4","5"],["2","3","6","4","7"])
CombinationFound = []
for i in e:
if i == a:
CombinationFound = True
break;
else:
CombinationFound = False
因为["1","2","3","4","5"]
它应该返回true和["1","3","2","4","5"]
有相同的价值观
为什么'CombinationFound'列表? – Bryan
你可以用'if if in a:'来检查项目'i'是否在'a'列表中。 – 2015-05-10 11:21:49