阵列迭代

-3

所以我有这个数组动态创建：阵列迭代

array = [ "Name can't be blank", "Email can't be blank", 
     "Email is invalid", "Password can't be blank", 
     "Password is too short (minimum is 6 characters)", 
     "Password confirmation can't be blank" ]

什么，我想通过这个数组迭代，如果有值：

"Password can't be blank"

验证是否存在价值：

"Password confirmation can't be blank"

并摆脱它。

所以返回的数组将是：

array = [ "Name can't be blank", "Email can't be blank", 
     "Email is invalid", "Password can't be blank", 
     "Password is too short (minimum is 6 characters)"]

非常感谢！

来源

2013-11-26 motamared

为什么要麻烦？如果密码为空白，我宁愿删除“太短”警告。 –

你刚刚写到：'array.delete（“密码确认不能为空”）如果array.include？（“密码不能为空”）' – user2422869

“询问代码的问题必须证明对问题得到解决包括尝试解决方案，为什么他们不工作，以及预期的结果。另请参见：[堆栈溢出问题清单]（http://meta.stackexchange.com/questions/156810/stack-overflow-question-清单）” –

这就是你如何做到的。 include?检查"Password can't be blank"。 delete删除该项目。

if array.include? "Password can't be blank" 
    array.delete "Password confirmation can't be blank" 
end

来源

2013-11-26 19:05:19 screenmutt

回答

相关问题