2017-08-13 22 views
0

我试图做一个UrlMatcher工厂AOT和功能工厂(动态路由模板)

export const dummyMatcher: UrlMatcher = matchUrlFn(sitemap as any, 'dummy'); 

export const routes: Routes = [ 
    { matcher: dummyMatcher, component: DummyComponent }, 
    { path: '**', component: DummyComponent }, 
]; 

但是,这并不与AOT工作... 我们如何处理功能工厂,AOT?

我试图

export function dummyMatcher(): UrlMatcher { return routeMatcher(sitemap as any, 'dummy'); } 

但是编译器抱怨:

类型“{匹配:()=> UrlMatcher; component:typeof DummyComponent; } ...'不能分配给'Route []'类型。


使用案例:

我需要匹配的网页(在NavigationNode[]描述),并使其在特定的模板组件。页面可以有多个网址(用于迁移目的,本地化的网址等)。 这里的匹配逻辑:

import { UrlSegment, UrlSegmentGroup, Route, UrlMatchResult } from '@angular/router'; 
import { inArray } from '@core/utils'; 

export interface NavigationNode { 
    ... 
    title?: string; 
    template?: string; 
    urls?: string[]; 
} 

/** 
* https://angular.io/api/router/UrlMatcher 
*/ 
export const UrlMatcherFactory = (conditions) => 
    (segments: UrlSegment[], group: UrlSegmentGroup, route: Route): UrlMatchResult => 
    conditions(segments) ? ({ consumed: segments }) : null; 

export const matchUrl = (nodes: NavigationNode[], template?: string) => 
    (segments: UrlSegment[]) => nodes 
    .filter(node => template ? node.template === template : true) 
    .some(node => inArray(node.urls)(`/${segments.join('/')}`)); 

export const matchUrlFn= (nodes: NavigationNode[], template?: string) => 
    UrlMatcherFactory(matchUrl(nodes, template)); 

这可以容易地扩展到使用不同的匹配,例如正则表达式:

export const matchRegex = (nodes: NavigationNode[]) => 
    (segments: UrlSegment[]) => nodes 
    .some(node => /\w+\/xyz/\d{1, 3}/.test(node.title)); /* bad example (: */ 

export const matchRegexFn = (nodes: NavigationNode[], template?: string) => 
    UrlMatcherFactory(matchRegex(nodes)); 

回答

0

matcher属性应该实现UrlMatcher类型:

export declare type UrlMatcher = (segments: UrlSegment[], group: UrlSegmentGroup, route: Route) => UrlMatchResult; 

所以我建议你更改代码如:

export function dummyMatcher(segments: UrlSegment[], group: UrlSegmentGroup, route: Route): UrlMatchResult { 
    const factory = matchUrlFn(sitemap as any, 'dummy'); 
    return factory(segments, group, route); 
} 
+0

是的,这个工程,它导致我最终版本'导出函数dummyMatcher():UrlMatcher {返回routeMatcher(sitemap任何'虚拟')。 }'...我试图让它保持轻量级,因为有匹配器的几条路线,所以在另一个地方隔离逻辑使得它更容易处理。谢谢。 – Sasxa

+0

不客气!是的,你的代码会更短:) – yurzui