虽然内内，而同时

Question

编辑 - 解决方案：：前而
我做了这个代码来显示比赛的记分牌第一位置移动到$sub = '';。
第一次：获取所有类别。
第二次：从类别中获取所有子类别。
第三次：从子类别获取所有记录。
问题是：
如果通过DESC的第一个循环顺序，它只打印第一个结果，并且在此类别中执行
。
如果我更改为ASC，则不会打印任何内容。
注意：并非每个子类别都有记录。

function SelectAllRecords() { 
    global $db; 
    try{ 
     $query = $db->query("SELECT id, name FROM category ORDER BY name DESC"); 
     while($category = $query->fetch(PDO::FETCH_ASSOC)) { 
      $categoryid = $category['id']; 
      $sub = ''; 
      $querysub = $db->query("SELECT id, id_category, name FROM category_sub WHERE id_category=".$categoryid); 
      while($subcategory = $querysub->fetch(PDO::FETCH_ASSOC)) { 
       if(!is_numeric($subcategory['id'])){ 
        continue; 
       }else{ 
        $subcategoryname = $subcategory['name']; 
        $sub .='<h2>'.$category['name'].'</h2> 
         <div class="widget-box"> 
          <div class="widget-title"> <span class="icon"><i class="icon-th"></i></span> 
           <h5>'.$subcategory['name'].'</h5> 
          </div> 
          <div class="widget-content nopadding"> 
           <table class="table table-bordered data-table" id="tabledata"> 
            <thead> 
             <tr> 
              <th class="columnadjust">Código</th> 
              <th>Competidor</th> 
              <th class="columnadjust">Ações</th> 
             </tr> 
            </thead> 
            <tbody id="tablecontent"> 
        '; 
        $record = $db->query("SELECT records.id as id, competitor.name as competitor, category.name as category, category_sub.name as subcategory, records.amplifier as amplifier, records.speaker as speaker, records.battery as battery, records.decibels as decibels, records.car as car FROM records LEFT JOIN competitor ON competitor.id = records.id_competitor LEFT JOIN category ON records.id_category = category.id LEFT JOIN category_sub ON records.id_subcategory = category_sub.id WHERE category_sub.name = '".$subcategoryname."' ORDER BY points ASC"); 
        while($records = $record->fetch(PDO::FETCH_ASSOC)) { 
         if(!is_numeric($records['id'])){ 
          $sub .= '<tr class="gradeX"></tr>'; 
         }else{ 
          $sub .= ' 
          <tr class="gradeX"> 
           <td class="columnadjust">'.$records['id'].'</td> 
           <td>'.$records['competitor'].'</td> 
           <td class="columnadjust"> 
            <a data-id="'.$records['id'].'" title="Editar" class="itemedit btn btn-warning btn-mini">Editar</a> 
           </td> 
          </tr>'; 
         } 
        } 
        $sub .= '</tbody></table></div></div>'; 
       } 
      } 
     } 
     $result = $sub; 
     echo $result; 
     return true; 
    } catch (PDOException $pe) { 
     return false; 
    } 

} 

Answer 1

也许它可以帮助重新格式化查询，以反映变量值蝙蝠（而不是稍后处理它们 - 这可能会或可能不会在你的软件的情况下）： 更换

$ querysub = $ db-> query（“SELECT id，id_category，name FROM category_sub WHERE id_category = $ categoryid”）;

与

$ querysub = $ DB->查询（ “选择ID，id_category，姓名FROM category_sub WHERE id_category =” $类别ID）;

而更换

$记录= $ DB->查询（“选择records.id为ID，competitor.name作为竞争对手，category.name类别，如category_sub.name子类别，记录放大器作为放大器，records.speaker作为扬声器，record.battery作为电池，records.decibels作为分贝，records.car作为汽车FROM记录LEFT JOIN竞争对手ON competitor.id = records.id_competitor LEFT JOIN类别ON记录.id_category = category .id LEFT JOIN category_sub ON records.id_subcategory = category_sub.id WHERE category_sub.name ='。$ subcategoryname。'ORDER BY points ASC“）;

与

$记录= $ DB->查询（“选择records.id为ID，competitor.name作为竞争对手，category.name类别，如category_sub.name子类别，记录。放大器作为放大器，records.speaker作为扬声器，record.battery作为电池，records.decibels作为分贝，records.car作为汽车FROM记录LEFT JOIN竞争者ON competitor.id = records.id_competitor LEFT JOIN类别ON records.id_category = category。 id LEFT JOIN category_sub ON records.id_subcategory = category_sub.id WHERE category_sub.name ='“。$ subcategoryname。“'ORDER BY points ASC”）;

而且，你是从执行在这一行停止整个代码：

if(!is_numeric($subcategory['id'])){ 
    continue; 
} 

更换continue与break只停止该迭代，并继续与下一个：

if(!is_numeric($subcategory['id'])){ 
    break; 
}