我遇到了一个我似乎无法解决的问题。请看下面的代码:Javascript代码运行良好...几乎所有的时间
<script>
function createFunctions() {
var first = ["", "", ""];
var second = ["", "", ""];
var func = ["", ""];
var sign = ["", ""];
for (i = 0; i < 3; i++) {
first[i] = (Math.round(Math.random() * 9) + 1);
second[i] = (Math.round(Math.random() * 9) + 1);
sign[i] = (Math.round(Math.random()));
if (sign[i] == "1") {
sign[i] = '+';
} else {
sign[i] = '-';
}
if (first < 2) {
func[i] = 'f(x) = x ' + sign[i] + ' ' + second[i] + '<p>';
} else {
func[i] = 'f(x) = ' + first[i] + 'x ' + sign[i] + ' ' + second[i] + '<br>';
}
}
for (i = 0; i < 3; i++) {
document.getElementById("createFunctions").innerHTML += 'Function ' + [i + 1] + ': ' + func[i];
}
//whichFunction=
findAnswers(first, second, sign);
}
function findAnswers(first, second, sign, rand) {
var num = ["", "", ""];
rand = (Math.round(Math.random() * 1));
document.getElementById("findAnswers").innerHTML = 'Which <b>one (or more)</b> of these functions holds true, when plugged in with the following <b>values of x</b>? (' + [rand + 1] + ')<br>';
for (i = 0; i < 3; i++) {
num[i] = (Math.round(Math.random() * 9));
}
for (i = 0; i < 3; i++) {
ans = 0;
if (sign[rand] == "+") {
ans = [first[rand] * num[i]] + second[rand];
} else {
ans = [first[rand] * num[i]] - second[rand];
}
document.getElementById("findAnswers").innerHTML += [i + 1] + '. You put in a ' + num[i] + ': ' + ans + '<br>';
}
}
</script>
<BODY onload=createFunctions()>
<b>A Machine Called Effex</b>
<p><input type="button" value="New Examples" onclick="history.go(0)" VALUE="Refresh"></p>
<p id="createFunctions"></p>
<p id="findAnswers"></p>
一切都很好。除了偶尔计算函数时,代码将乘以x,然后简单地将第二个值连接到第一个,而不是添加(或减去)。
不应该是第15行的第一个[i] <2'吗? – mynawaz
尝试在第36和38行的'[first [rand] * num [i]] + second [rand]'中将最外方括号更改为圆括号,并且还使用parseInt在这些行上将操作数强制转换为int – mynawaz
更改了数组从var array = [“”,“”,“”]'到'var array = []',因为它只是创建一个空数组,而'i'在for循环中完成其余部分。看看这里:http://jsfiddle.net/zzx5w79a/也许你想包括这个链接到你的问题。我无法找到“偶尔..,代码相乘..” – caramba