来自多个JOINed表的SUMs MSSQL

Question

我正在尝试生成基于多个表的动态计算显示未结余额的报表。目前，该报告是使用运行查询的服务器端语言生成的，循环遍历查询并针对结果运行另一个查询。我的目标是执行MSSQL中的所有计算。

下面是表/一些示例性数据列：

TEST_ORDER表

orderid customerid serviceamount 
1001  2001     75.00 
1002  2002     85.00 
1003  2001     25.00 
1004  2003     10.00 

TEST_CUSTOMER表

customerid customername 
2001   'Initech' 
2002   'Dunder Mifflin' 
2003   'Paper Street Soap Co' 

TEST_ORDERITEM表

orderitemid orderid itemamount 
5001   1001   50.00 
5002   1001   150.00 
5003   1002   15.00 
5004   1004   200.00 
5005   1004   200.00 

TEST_TRANSACTION表

transactionid orderid amount 
9001    1001  75.00 
9002    1002  25.00 
9003    1002  50.00 
9004    1003  55.00 
9005    1001  50.00 
9006    1001  150.00 

我正在寻找的结果是：

orderid customername   totalorder totalpaid  balance 
1001  'Initech'     275.00  275.00  0.00 
1002  'Dunder Mifflin'   100.00  75.00  -25.00 
1003  'Initech'     25.00  55.00  30.00 
1004  'Paper Street Soap Co'  410.00  0.00  -410.00 

这是我想出了查询：

SELECT 
    o.orderid, c.customername, o.serviceamount, 
    (o.serviceamount + SUM(i.itemamount)) AS totalorder, 
    SUM(t.amount) AS totalPaid, 
    (SUM(t.amount) - (o.serviceamount + SUM(i.itemamount))) AS balance 

FROM 
    test_order o 
    INNER JOIN test_customer c ON o.customerID = c.customerID 
    LEFT OUTER JOIN test_transaction t ON o.orderID = t.orderID 
    LEFT OUTER JOIN test_orderitem i ON o.orderID = i.orderID 

WHERE 
    1=1 

GROUP BY 
    o.orderid, c.customername, o.serviceamount, 
    o.serviceamount 

而且这里是结果：

orderid customername   totalorder totalpaid  balance 
1001  'Initech'     675.00  550.00  -125.00 
1002  'Dunder Mifflin'   115.00  75.00  -40.00 
1003  'Initech'     null  55.00  null 
1004  'Paper Street Soap Co'  410.00  null  null 

我遇到的问题是：1。 记录test_orderitem是重复的，例如对于订单1002，服务金额为85美元，只有15美元的订单项，然而，总订单计算为115美元。我认为问题与JOIN迭代两次有关。 2.没有记录返回时（出于显而易见的原因），显示'空'。我还没有开始这方面的工作，因为我已经在MySQL中进行了测试，并且我想在将它返回到MSSQL之前找出JOIN问题。

谢谢您也许能提供任何援助......

Answer 1

对于MS-SQL：在这里，你，只需更换与最后的查询表名你自己。

DECLARE @Test_Order TABLE (orderid int, customerid int, serviceamount money) 
INSERT INTO @Test_Order(orderid,customerid,serviceamount) 
SELECT 1001,2001,75.00 UNION ALL 
SELECT 1002,2002,85.00 UNION ALL 
SELECT 1003,2001,25.00 UNION ALL 
SELECT 1004,2003,10.00 

DECLARE @Test_Customer TABLE (customerid int, customername varchar(100)) 
INSERT INTO @Test_Customer(customerid,customername) 
SELECT 2001,'Initech' UNION ALL 
SELECT 2002,'Dunder Mifflin' UNION ALL 
SELECT 2003,'Paper Street Soap Co' 

DECLARE @Test_OrderItem TABLE (orderitemid int, orderid int, itemamount money) 
INSERT INTO @Test_OrderItem (orderitemid, orderid, itemamount) 
SELECT 5001,1001,50.00 UNION ALL 
SELECT 5002,1001,150.00 UNION ALL 
SELECT 5003,1002,15.00 UNION ALL 
SELECT 5004,1004,200.00 UNION ALL 
SELECT 5005,1004,200.00 

DECLARE @Test_Transaction TABLE (transactionid int, orderid int, amount money) 
INSERT INTO @Test_Transaction (transactionid, orderid, amount) 
SELECT 9001,1001,75.00 UNION ALL 
SELECT 9002,1002,25.00 UNION ALL 
SELECT 9003,1002,50.00 UNION ALL 
SELECT 9004,1003,55.00 UNION ALL 
SELECT 9005,1001,50.00 UNION ALL 
SELECT 9006,1001,150.00 


SELECT O.orderid, 
     C.customername, 
     SUM(ISNULL(O.serviceamount,0)+ISNULL(I.itemamount,0)) AS totalorder, 
     SUM(ISNULL(T.amount,0)) AS totalpaid, 
     (SUM(ISNULL(T.amount,0))) - (SUM(ISNULL(O.serviceamount,0)+ISNULL(I.itemamount,0))) as balance 
FROM @Test_Customer C 
JOIN @Test_Order O 
    ON C.customerid=O.customerid 
LEFT JOIN (SELECT orderid, SUM(itemamount) AS itemamount FROM @Test_OrderItem GROUP BY orderid) I 
    ON O.orderid=I.orderid 
LEFT JOIN (SELECT orderid, SUM(amount) AS amount FROM @Test_Transaction GROUP BY orderid) T 
    ON O.orderid=T.orderid 
GROUP BY O.orderid, C.customername 
ORDER BY O.orderid, C.customername 

Answer 2

这给一试：

SELECT 
    summary.orderid, 
    summary.customername, 
    summary.totalorder, 
    summary.totalpaid, 
    summary.totalorder - summary.totalpaid AS balance 
FROM 
    (SELECT 
     o.orderid, 
     c.customername, 
     (SELECT SUM(oi.itemamount) FROM test_orderitem oi WHERE oi.orderid = o.orderid) AS totalorder, 
     (SELECT IFNULL(SUM(t.amount), 0) FROM test_transaction t WHERE t.orderid = o.orderid) AS totalpaid 
    FROM 
     test_order o, 
     test_customer c 
    WHERE 
     o.customerid = c.customerid) summary 

Answer 3

http://sqlfiddle.com/#!9/ae0be/1

SELECT 
    o.orderid, 
    c.customername, 
    (coalesce(o.serviceamount,0)+coalesce(i.itemsum,0)) totalorder, 
    t.t_sum totalpaid, 
    (coalesce(t.t_sum,0)-coalesce(o.serviceamount,0)-coalesce(i.itemsum,0)) balance 
FROM TEST_ORDER o 
LEFT JOIN (
    SELECT orderid, SUM(itemamount) itemsum 
    FROM TEST_ORDERITEM 
    GROUP BY orderid 
) i 
ON o.orderid = i.orderid 
LEFT JOIN (
    SELECT orderid, SUM(amount) t_sum 
    FROM TEST_TRANSACTION 
    GROUP BY orderid 
) t 
ON o.orderid = t.orderid 
LEFT JOIN TEST_CUSTOMER c 
ON o.customerid = c.customerid 
ORDER BY o.orderid