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在故事板,我想加上一个滚动视图按钮,并分配到按钮IOS 7.0:按钮动作坠毁
- (IBAction)likeFood:(id)sender{NSLog(@"liked")};
的行动,但它坠毁,当我在iPhone模拟器中运行,输出说:
Terminating app due to uncaught exception `'NSUnknownKeyException', reason: [<DetailFoodViewController 0xf034aa0> setValue:forUndefinedKey:]: this class is not key value coding-compliant for the key like.'
任何人都可以帮忙吗?
请分享您的代码! –
[问] - 请为你的按钮动作添加代码。 –
里面什么也没有,只是 - (IBAction)likeFood:(id)sender NSLog(@“liked”); } – Zheng