由于我的内部连接,Hiberate正在创建重复的对象。查询将父表与子表连接起来(父表与父子关系一对多)。Hibernate创建重复对象
数据:
Category (Parent)
ID|Name
1|A
2|B
Testcase (Child)
ID|CategoryID|Name|Run
1|1|A|500
2|1|B|500
3|1|C|500
4|2|D|600
从加入的结果,其中运行= 500
CategoryID|TestcaseID|TestCase Name
1|1|A
1|2|B
1|3|C
从此,我希望Hibernate来创建一个类的对象包含3个测试用例对象的列表。相反,它创建了3个类别对象,每个对象都带有3个测试用例的正确列表
类别[ID = 1,name = FOO,testCases = [TestCase [ID = 1,name = A,runId = 500],TestCase [ 2,name = B,runId = 500],TestCase [ID = 3,name = C,runId = 500]]]
类别[ID = 1,name = FOO,testCases = [TestCase [名称= C,runId = 500]]]
类别[ID = 1,名称= A,runId = 500],TestCase [ID = 2,名称= B,runId = 500] name = FOO,testCases = [TestCase [ID = 1,name = A,runId = 500],TestCase [ID = 2,name = B,runId = 500],TestCase [ID = 3,name = C,runId = 500 ]]]
型号:
@Entity
@Table(name = "CATEGORY")
public class Category implements Serializable
{
private static final long serialVersionUID = 1L;
@Id
@Column(name = "CATEGORYID")
private int ID;
@Column(name = "CATEGORYNAME")
private String name;
@OneToMany(fetch = FetchType.EAGER)
@JoinColumn(name = "CATEGORYID")
@Filter(name = "TEST_RUN_ID_FILTER")
private Collection<TestCase> testCases;
}
@Entity
@Table(name = "TESTCASE_NEW")
@FilterDef(name = "TEST_RUN_ID_FILTER", defaultCondition = "TESTRUNID in (:IDS)", parameters = { @ParamDef(name = "IDS", type = "int") })
public class TestCase implements Serializable
{
private static final long serialVersionUID = 1L;
@Id
@Column(name = "TESTCASEID")
private int ID;
@Column(name = "TESTCASENAME")
private String name;
@Column(name = "STATUS")
private String status;
@Column(name = "TESTRUNID")
private int testRunId;
}
DAO:
public List<Category> getAllCategoriesForTestRuns(List<Integer> testRunIDs)
{
Session session = getSession();
session.enableFilter("TEST_RUN_ID_FILTER")
.setParameterList("IDS", testRunIDs);
Query query = session.createQuery("select c from Category c inner join c.testCases tc");
List<Category> result = query.list();
return result;
}
我可以,如果我恰克的HQL查询来选择不同的,以获得正确的结果,但我想知道是否有更正确的方式。从我的谷歌搜索中,我尝试添加@Fetch(FetchMode.SELECT)到类别中的testCase列表,但没有任何效果。
谢谢!
非常有帮助谢谢。当你将它看作结果集时,它确实有意义!我一直将每个结果对象添加到一个集合中,以滤除总是感觉错误的重复。 – JLove 2014-02-05 16:46:06