透视表字符串在透视列下分组？

JOB  ENAME 
-------- ---------- 
ANALYST SCOTT 
ANALYST FORD 
CLERK  SMITH 
CLERK  ADAMS 
CLERK  MILLER 
CLERK  JAMES 
MANAGER JONES 
MANAGER CLARK 
MANAGER BLAKE 
PRESIDENT KING 
SALESMAN ALLEN 
SALESMAN MARTIN 
SALESMAN TURNER 
SALESMAN WARD

我想格式化结果设定，使得每个职业都有自己的列：透视表字符串在透视列下分组？

CLERKS ANALYSTS MGRS PREZ SALES 
------ -------- ----- ---- ------ 
MILLER FORD  CLARK KING TURNER 
JAMES SCOTT  BLAKE  MARTIN 
ADAMS    JONES  WARD 
SMITH

我试图

SELECT ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN from 
(
    SELECT ename, job from emp 
) as st 
pivot 
(
    SELECT ename 
    FOR job in (ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN) 
) as pivottable

我得到这些错误

Msg 156，Level 15，State 1，Line 7
错误的同步在关键字'SELECT'附近收税。
Msg 156，Level 15，State 1，Line 8
关键字'in'附近的语法不正确。

如何使用透视将字符串分组在透视列下？

来源

2013-03-11 mr_eclair

@Downvoter关心评论？我的问题没有什么是错的。 – 2013-05-07 13:44:51

当然，这是一个有趣的问题。来自我的+1 ... – 2016-07-01 04:20:40

当您使用PIVOT函数时，您需要使用聚合函数。一个PIVOT的语法是：

从MSDN：

SELECT <non-pivoted column>, 
    [first pivoted column] AS <column name>, 
    [second pivoted column] AS <column name>, 
    [last pivoted column] AS <column name> 
FROM 
    (<SELECT query that produces the data>) 
    AS <alias for the source query> 
PIVOT 
(
    <aggregation function>(<column being aggregated>) 
FOR 
[<column that contains the values that will become column headers>] 
    IN ([first pivoted column], [second pivoted column], 
    ... [last pivoted column]) 
) AS <alias for the pivot table> 
<optional ORDER BY clause>;

一个字符串，你将需要使用任一MIN()或MAX()聚合函数。您将遇到的问题是这些函数将只为每列返回一个值。

因此，要使PIVOT正常工作，您需要提供一个明确的值，以便在GROUP BY期间保持行分离。

对于你的榜样，您可以使用row_number()：

SELECT ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN 
from 
(
    SELECT ename, job, 
    row_number() over(partition by job order by ename) rn 
    from emp 
) as st 
pivot 
(
    max(ename) 
    FOR job in (ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN) 
) as pivottable

见SQL Fiddle with Demo。

的row_number()创建分配给每个行的job，当你应用聚合函数，并在PIVOT你仍然会得到不同的行的GROUP BY一个独特的价值。

来源

2013-03-11 11:25:07 Taryn

透视表字符串在透视列下分组？

回答

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