根据“divider”字符将PHP字符串划分为排列的子字符串

Question

我想要做的是将一个PHP字符串分成一组子字符串，这些子字符串根据开始这些子字符串的“divider”字符分组为数组。字符*,^和%被保留为分隔符。所以，如果我有串"*Here's some text^that is meant*to be separated^based on where%the divider characters^are"，应该分裂并放置在阵列像这样：

array(2) { 
    [0] => "*Here's some text" 
    [1] => "*to be separated" 
} 

array(3) { 
    [0] => "^that is meant" 
    [1] => "^based on where" 
    [2] => "^are" 
} 

array(1) { 
    [0] => "%the divider characters" 
} 

我完全失去了在这一个。有谁知道如何实现这一点？

Answer 1

，如果你想你不为$matches[0]所以取消它问：

preg_match_all('/(\*[^\*\^%]+)|(\^[^\*\^%]+)|(%[^\*\^%]+)/', $string, $matches); 
$matches = array_map('array_filter', $matches); 

print_r($matches); 

的array_filter()去除捕获组子阵列空瓶给在这个问题

Answer 2

另一个所示的阵列方法（优化）..

$matches = array(); 
preg_match_all('/[\*\^\%][^\*\^\%]+/', $str, $matches); 
var_dump($matches);