我有一个数据,其中300万条记录的start.time和end.time作为两个变量。前10个obs如下:计算R中的时间差异
start.date start.time end.date end.time
1 2012-07-13 15:01:32 2012-07-13 15:02:42
2 2012-07-05 18:26:31 2012-07-05 18:27:19
3 2012-07-14 20:23:21 2012-07-14 20:24:11
4 2012-07-29 16:09:54 2012-07-29 16:10:48
5 2012-07-21 14:58:32 2012-07-21 15:00:17
6 2012-07-04 15:36:31 2012-07-04 15:37:11
7 2012-07-22 18:28:31 2012-07-22 18:28:50
8 2012-07-09 21:08:42 2012-07-09 21:09:02
9 2012-07-05 09:44:52 2012-07-05 09:45:05
10 2012-07-02 18:50:47 2012-07-02 18:51:38
我需要计算start.time和end.time之间的差异。
我用下面的代码:
mbehave11$diff.time <- difftime(mbehave11$end.time, mbehave11$start.time, units="secs")
但我收到此错误:
Error in as.POSIXlt.character(x, tz, ...) :
character string is not in a standard unambiguous format
In addition: Warning messages:
1: In is.na.POSIXlt(strptime(xx, f <- "%Y-%m-%d %H:%M:%OS", tz = tz)) :
Reached total allocation of 1535Mb: see help(memory.size)
你能提供一个可重现的例子吗?你可以阅读这个更多的信息:http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example – Dason