我有一个程序,其中有2个进程java:processA和processB(2个进程java.exe不是2个线程)。 我用下面的代码块从过程A至调用进程B这个代码被包裹在RunTask类下面从另一个java进程调用java使其停止
public class RunTask implements Callable<Object> {
private String runParams;
public String getRunParams() {
return runParams;
}
public void setRunParams(String runParams) {
this.runParams = runParams;
}
@Override
public Object call() throws Exception {
try {
//System.out.println("run:" + runParams);
Process procB = Runtime.getRuntime().exec("java -jar processB.jar);
DataInputStream ls_in = new DataInputStream(procB.getInputStream());
String ls_str;
while ((ls_str = ls_in.readLine()) != null) {
System.out.println(ls_str);
}
} catch (Exception exp) {
exp.printStackTrace();
}
return null;
}
}
和主要类别I执行人
ExecutorService eservice = Executors.newSingleThreadExecutor();
while (1 == 1) {
String stringParams = getFilesNeedToImportAsString();
if (stringParams.trim().isEmpty()) {
long l1 = System.currentTimeMillis() - l;
System.out.println("all time" + l1/1000);
System.exit(100);
}
RunTask runTask = new RunTask();
runTask.setRunParams(SystemInfo.RUN_COMMAND + stringParams);
Future<Object> objectFuture = eservice.submit(runTask);
while (!objectFuture.isDone()) {
System.out.println("waiting the task running");
Thread.sleep(500);
}
}
但是,当异常发生在进程B这两个进程( processA,进程B)似乎被暂停在进程B这是代码的运行
public Object call() {
try {
MutationResult result = mutator.execute();
return "ok";
} catch (Exception exp) {
exp.printStackTrace();
System.out.println("error on " + Thread.currentThread().getName() + "failed begin retry " + (++retryCount));
call();
System.out.println(retryCount + " completed");
return "ok";
}
}
如果我运行进程B单独(通过命令行站),它永远不会发生,或当这个问题发生我使用taskmanager杀死proceesA(被调用者),processB继续运行
请任何一个给我这个问题的解决方案!
感谢spaniard StackOverflowException可能发生在这里!我已经修复了它:D:D –