2013-01-10 99 views
1

我正在放在一起交叉表,我想要一个按月分组的多个列值(所有数字)的报告。这是我使用的SQL。我知道这不会带来预期的结果。每个“timex”列中都有一个不同的数字。我想要一个查询,它将返回按月分组的列的总和。MS Access交叉表查询 - 按月报告的列总数

TRANSFORM Sum(tblTimeTracking.time1+ tblTimeTracking.time2+ tblTimeTracking.time3+ tblTimeTracking.time4+ tblTimeTracking.time5+ tblTimeTracking.time6+ tblTimeTracking.time7+ tblTimeTracking.time8+ tblTimeTracking.time9+ tblTimeTracking.time10+ tblTimeTracking.time11+ tblTimeTracking.time12+ tblTimeTracking.time13+ tblTimeTracking.time14+ tblTimeTracking.time15+ tblTimeTracking.time16+ tblTimeTracking.time17+ tblTimeTracking.time18+ tblTimeTracking.time19+ tblTimeTracking.time20+ tblTimeTracking.time21+ tblTimeTracking.time22) AS Total SELECT tbl_vlookup.Manager AS Manager FROM tbl_vlookup INNER JOIN tblTimeTracking ON tbl_vlookup.[Associate Name] = tblTimeTracking.Associate GROUP BY tbl_vlookup.Manager PIVOT Format([Day],"yyyy-mm");

Associate Day   Time 1 Time 2 Time 3 Time 4 Time 5 Time 6 Time 7 
John Smith 12/1/9999  1   0  0  5.5  1  0.25 0.25 
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你是说你有一个22个时间表的列表?如果是这样,为什你需要用UNION查询来压扁它。 – Fionnuala

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我这样做。他们都是独一无二的。这是一个劳动力跟踪器。时间1将是休息时间,时间2 =文件等...我想找到按月排序的所有列的总数 – Chris568524

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请发布样本数据。 – Fionnuala

回答

1

事情是这样的:

TRANSFORM Sum(q.Time1) AS SumOfTime1 
SELECT q.Associate, q.Day 
FROM (SELECT t.Associate, t.Day, t.Time1,"Time1" As TimeType 
FROM tbl t 
UNION ALL 
SELECT t.Associate, t.Day, t.Time2,"Time2" As TimeType 
FROM tbl t 
UNION ALL 
SELECT t.Associate, t.Day, t.Time3,"Time3" As TimeType 
FROM tbl t) AS q 
GROUP BY q.Associate, q.Day 
PIVOT q.TimeType; 

正如我所说,你需要拼合表。它似乎只是不同类型的数据:)