我一直在Python中编写基于文本的RPG代码时遇到了麻烦。该RPG为每个位置使用一个类,并且可以扫描游戏目录中的地图并将其添加到大型3D列表中。这个3D列表中的每个元素都是一个列表本身,包含4个值:坐标,名称,简短描述和地图的原始数据。坐标未正确分配(Python 3.3)
但是,当我使用该函数更新此映射时,尽管看起来运行正常,但在打印列表元素时却没有显示预期值。
我在我的/ maps文件夹的子目录中有4个测试map.txt文件,每个文件都有三次检查坐标的准确性。
我的问题减少到代码如下:
# Imports:
import os
import sys
from random import randint
# Definitions
def create_maps_list():
"""Creates a blank list of 100*100*100 zeros."""
x_list, y_list, z_list, attr_list = [], [], [], []
for _ in range(4):
attr_list.append(0)
for _ in range(100):
z_list.append(attr_list)
for _ in range(100):
y_list.append(z_list)
for _ in range(100):
x_list.append(y_list)
global maps_list
maps_list = x_list
def update_maps_list(maps_list):
"""Updates maplist by scanning the maps dir."""
listdirs = os.listdir(os.getcwd() + "\maps") # List folder names in /maps
for mapdir in listdirs:
mapfile = open("maps/{0}/map.txt".format(mapdir)) # Open map.txt
linelist = list(mapfile)
desc = open("maps/{0}/description.txt".format(mapdir)).read()
mapdata = linelist[2:]
name = linelist[1]
coordsline = linelist[0]
coords = []
for num in coordsline.split():
coords.append(int(num))
x = coords[0]
y = coords[1]
z = coords[2]
print("Name: ", name, "Assigned to coords: ", coords, "\n")
maps_list[x][y][z] = [coords, name, desc, mapdata]
return maps_list
# Assignments:
maps_list = []
list_data = []
# Execution
create_maps_list()
maps_list = update_maps_list(maps_list)
# Output
print()
print("Expected output: [0, 0, 0] Initial Building.")
print(maps_list[0][0][0][0], maps_list[0][0][0][1])
实际输出如下:
Name: East Building
Assigned to coords: [1, 0, 0]
Name: Heaven!
Assigned to coords: [0, 0, 1]
Name: Initial Building
Assigned to coords: [0, 0, 0]
Name: North Building
Assigned to coords: [0, 1, 0]
Expected output: [0, 0, 0] Initial Building.
[0, 1, 0] North Building
[Finished in 0.3s]
任何援助将不胜感激(包括不直接相关的问题 - 我有一个偷偷摸摸的怀疑,以这种方式存储坐标不是做事情的最佳方式!)
看到这个问题:http://stackoverflow.com/questions/1959744/python-list-problem – happydave