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我有一个Socket
在Java中,并发送一个DatagramPacket
,我需要从PHP页面读取,然后将其写入文件,但我找不到一种方法来做到这一点。如何获得datagrampacket在PHP
这是Java的插座代码:
private void openSocket(){
try {
client = new DatagramSocket();
System.out.println(" Socket client açıldı.. ");
} catch (Exception e) {
System.out.println(" PosyByte : Open Socket Hata " + e.toString());
}
}
private InetAddress getIpaddress(String adress){
try {
InetAddress ipaddress = InetAddress.getByName(adress);
return ipaddress;
} catch (Exception e) {
System.out.println(" PosyByte : getIpaddress Hata! " + e.toString());
return null;
}
}
private DatagramPacket createDatagramPacket(byte[] buf , int length , InetAddress ipadress , int port){
DatagramPacket dp = new DatagramPacket(buf, length, ipadress, port);
return dp;
}
private void sendDataOnSocket (DatagramPacket udp){
try {
client.send(udp);
} catch (IOException ex) {
System.out.println(" PosyByte : SendDataonSocket Hata! " + ex.toString());
}catch (Exception e){
System.out.println(" PosyByte : SendDataonSocket Hata! " + e.toString());
}
}
private void closeSocket(){
client.close();
System.out.println(" Socket client kapandı.. ");
}
这可能有助于阅读:http://www.phpgangsta.de/udp-nachrichten-versenden-und-empfangen(这是德语,但有很好的例子,说明自己)在文章的底部是什么我想你正在寻找。 – Fildor
谢谢,我要试一试 – Acablack