我想弄清楚paypal API,并且我有下面的代码,它应该进行调用,获取访问令牌,然后进行API调用。第一部分工作(直到$accesstoken
行),并正确返回访问令牌,但第二部分不返回任何内容。这是应该模仿的代码可以在这里找到:Make Your First CallPayPal API,Curl不返回任何输出
$url = "https://api.sandbox.paypal.com/v1/oauth2/token";
$headers = array(
'Accept' => 'application/json',
'Accept-Language' => 'en_US',
);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE);
curl_setopt($ch, CURLOPT_POSTFIELDS, 'grant_type=client_credentials');
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_USERPWD, $clientID . ':' . $clientSecret);
$curl = curl_exec($ch);
$x = json_decode($curl, TRUE);
print_r($x);
$accesstoken = $x['access_token'];
$headers2 = array(
'Content-Type' => 'application/json',
'Authorization' => 'Bearer' . $accesstoken
);
$data = array(
"intent" => "sale",
"redirect_urls" => array(
"return_url" => "http://example.com/your_redirect_url/",
"cancel_url" => "http://example.com/your_cancel_url/"
),
"payer" => array(
"payment_method" => "paypal"
),
"transactions" => array(
"transactions" => array(
"total" => ".99",
"currency" => "USD"
)
)
);
$saleurl = "https://api.sandbox.paypal.com/v1/payments/payment";
$sale = curl_init();
curl_setopt($sale, CURLOPT_URL, $saleurl);
curl_setopt($sale, CURLOPT_VERBOSE, TRUE);
curl_setopt($sale, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($sale, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($sale, CURLOPT_SSL_VERIFYHOST, FALSE);
curl_setopt($sale, CURLOPT_POSTFIELDS, json_encode($data));
curl_setopt($sale, CURLOPT_HTTPHEADER, $headers2);
$finalsale = curl_exec($sale);
$verb = json_decode($finalsale, TRUE);
print_r($verb);
卷翘不作完整意义上的对我来说,任何帮助,将不胜感激。
更新: 我改变了标题的格式:
$headers2 = array(
'Content-Type: application/json',
'Authorization: Bearer ' . $accesstoken
);
按其中一个答案。现在,它显示:
[name] => MALFORMED_REQUEST
[message] => Incoming JSON request does not map to API request
[information_link] => https://developer.paypal.com/webapps/developer/docs/api/#MALFORMED_REQUEST
[debug_id] => f53a882702a04
在你的产品代码总是验证同行和验证安全主机:http://docforge.com/wiki/PHP/Curl –
从不假定外部调用成功。你不检查curl_exec()中的返回值是否为boolean false,这表示失败。你只需要返回的值,并尝试json_decode它。至少你应该更像'if(($ result = $ curl_exec($ handle)=== FALSE){die(curl_error($ handle));}' –
@Matt,我现在正在测试,但是($结果= curl_exec($ sale))=== FALSE){echo“Error。”; die(curl_error($ sale))当然,SSL是一个必须的,一旦我在线 –