不能使用非静态方法的线程

Question

我想从线程中调用一个名为UpdateResults()的非静态方法。这是我的代码：

class Live 
{ 
    Thread scheduler = new Thread(UpdateResults); 

    public Live() 
    { 
     scheduler.Start(); 
    } 

    public void UpdateResults() 
    { 
     //do some stuff 
    } 
} 

，但我得到这个错误：

A field initializer can not refer to the property, method or non-static field 'Live.UpdateResults()'

我怎样才能解决这个问题？

Answer 1

这与Thread无关。有关详细情况，请参阅this问题。 解决您的问题，改变你的类，如下所示：

class Live 
{ 
    Thread scheduler; 

    public Live() 
    { 
     scheduler = new Thread(UpdateResults); 
     scheduler.Start(); 
    } 

    public void UpdateResults() 
    { 
     //do some stuff 
    } 
} 

由于乔恩斯基特提到了上述问题，从C＃4规范的部分10.5.5.2：

A variable initializer for an instance field cannot reference the instance being created. Thus it is a compile-time error to reference this in a variable initializer, because it is a compile-time error for a variable initializer to reference any instance member through a simple-name.

当你写new Thread(UpdateResults)你真的在写new Thread(this.UpdateResults)。

Answer 2

C＃6.0解决方案：改变分配（=）来初始化=>

class Live { 
    // Please, note => instead of = 
    Thread scheduler => new Thread(UpdateResults); 

    public Live() { 
     scheduler.Start(); 
    } 

    public void UpdateResults() { 
     //do some stuff 
    } 
    }