打开和关闭应用从Java

Question

我试图使用ProcessBuilder在CMD.EXE启动应用程序，等待它完成，然后将其关闭。到目前为止，我尝试过：

String[] cmdline=new Stirng{}("cmd.exe","/C","start",application_and_parameters); 
ProcessBuilder processBuilder = new ProcessBuilder(cmdline); 
Process p = processBuilder.start(); 
//get error and input streams 
int exitVal = p.waitFor(); 

它按预期打开窗口，但未关闭。我想：

p.destroy() 

并发送退出命令：

BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(p.getOutputStream())); 
writer.write("exit"); 
writer.flush(); 

但没有成功，CMD住宿。任何人都可以提出解决方案

Answer 1

删除开始，它会直接执行的过程，而无需打开命令提示符，所以你不会需要关闭它manually.Below是你的代码片段作为一个例子

 

String[] cmdline=new String[]{"cmd.exe","/C","notepad.exe"}; 
       ProcessBuilder processBuilder = new ProcessBuilder(cmdline); 
       Process p = processBuilder.start(); 
       //get error and input streams 
       int exitVal = p.waitFor(); 
       System.out.println(exitVal);