COUNTing有多少行GROUPED BY

Question

SELECT id,name,SUM(`lsa`) AS lst FROM 
    table_a AS sn, 
    table_b AS fb 
WHERE sn.uid=fb.uid 
    AND COUNT(`lsa`)=6 
GROUP BY sn.uid 
ORDER BY SUM(`lsa`) 

我有一个像这样的查询，显然AND COUNT(lsa)=6位是无效的语法。我很迷茫。

我想实现的是一个清单，由lsa总和下令，由uid分组，只有有6项为UID，即在“组”。我该怎么做？

Answer 1

它是有效的聚集过滤，但需要进入HAVING条款，而不是WHERE所以使用

SELECT id, 
     name, 
     SUM(`lsa`) AS lst 
FROM table_a AS sn 
     JOIN table_b AS fb 
     ON sn.uid = fb.uid /*Using Explicit Join syntax*/ 
GROUP BY sn.uid,   /*And avoiding MySQL GROUP BY extension*/ 
      id, 
      name 
HAVING COUNT(`lsa`) = 6 
ORDER BY SUM(`lsa`) 

代替。