打印解决方案（新的C）

-1

我弄不明白为什么我的程序不会打印最终解决方案（totalDough）。输入是8,10,12然后40,100和200：打印解决方案（新的C）

const int DOUGH_PER_SQFT = 0.75; 
const int INCHES_PER_FEET = 12; 
#define M_PI 3.14159265358979323846 

int main(){ 

    // Declare and initialize variables 

    int smallRIn; 
    printf("What is the radius of your small pizza, in inches?\n"); 
    scanf("%d", &smallRIn); 
    int mediumRIn; 
    printf("What is the radius of your medium pizza, in inches?\n"); 
    scanf("%d", &mediumRIn); 
    int largeRIn; 
    printf("What is the radius of your large pizza, in inches?\n"); 
    scanf("%d", &largeRIn); 


    // Get number of pizzas sold 
    int smallSold; 
    printf("How many small pizzas do you expect to sell this week?\n"); 
    scanf("%d", &smallSold); 
    int mediumSold; 
    printf("How many medium pizzas do you expect to sell this week?\n"); 
    scanf("%d", &mediumSold); 
    int largeSold; 
    printf("How many large pizzas do you expect to sell this week?\n"); 
    scanf("%d", &largeSold); 

    // Convert radii to feet 

    double smallRFeet, mediumRFeet, largeRFeet; 
    smallRFeet = smallRIn/INCHES_PER_FEET; 
    mediumRFeet = mediumRIn/INCHES_PER_FEET; 
    largeRFeet = largeRIn/INCHES_PER_FEET; 

    // Calculate top surface areas of each type of pizza. 

    double areaSmall, areaMedium, areaLarge; 
    areaSmall = smallSold*M_PI*pow(smallRFeet,2); 
    areaMedium = mediumSold*M_PI*pow(mediumRFeet,2); 
    areaLarge = largeSold*M_PI*pow(largeRFeet,2); 

    // Print solution 
    double dough; 
    dough = areaSmall+areaMedium+areaLarge; 
    double total_dough; 
    total_dough = dough * DOUGH_PER_SQFT; 

    printf("The total amount of dough you need to order this week is", total_dough); 

    return 0; 
}

我在做什么错？

来源

2014-09-21 corvette1

我希望较小的一段代码，不为你工作，你尝试过什么更好的标题和更多，以及它如何失败。 – 2014-09-21 16:43:13

const int DOUGH_PER_SQFT = 0.75;

这是价值为int和INT的不是浮点数，所以这相当于：

这基本上意味着我n您的最终方程

total_dough = dough * DOUGH_PER_SQFT;

它将评估为0，因为每平方英尺面团等于0

这可以通过更改纠正：

const int DOUGH_PER_SGFT = 0.75

到：

const double DOUGH_PER_SGFT = 0.75

来源

2014-09-21 14:57:10 Chantola

请注意，Clang警告这个：*警告：从'double'到'int'的隐式转换将值从0.75改变为0 *。使用列表初始化会导致错误。 – chris 2014-09-21 15:01:46

谢谢。结合上面的答案，就是这样。现在我只需要输出来匹配676.751417 .... lbs的测试用例答案。那里有任何想法？我得到471.238？ – corvette1 2014-09-21 15:20:16

尝试将#define M_PI 3.14159265358979323846更改为const double M_PI = 3.14159265358979323846 – Chantola 2014-09-21 15:25:41

打印代码为打印格式为，您显然忘记了参数total_dought的格式。

我建议使用编译器标志来生成警告，如果你使用gcc，add -Wall。

关于解决方案，替换：

printf("The total amount of dough you need to order this week is", total_dough);

通过

printf("The total amount of dough you need to order this week is %f", total_dough);

来源

2014-09-21 14:56:42 superjedi

谢谢，学习python之后的第一个程序... – corvette1 2014-09-21 15:18:19

有两个问题：

const int DOUGH_PER_SQFT = 0.75;

的整数着店小数所以它转换成宏：

#define DOUGH_PER_SQFT 0.75

而且

printf("The total amount of dough you need to order this week is", total_dough);

不打印的价值。它转换为：

printf("The total amount of dough you need to order this week is%f", total_dough);

正在运行的代码是：http://ideone.com/aucOlW

来源

2014-09-21 15:44:01

打印解决方案（新的C）

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