PDO“在重复密钥更新”准备语句

我正在尝试基于this thread第一次准备好的语句。到目前为止，我收到错误消息SQLSTATE[HY000]: General error: 1 near "ON": syntax error下面是该查询随后try块：PDO“在重复密钥更新”准备语句

$query = "INSERT INTO results2015_2016 ('id','ata','atc','atcommon','atn','ats','atsog','hta','htc','htcommon','htn','hts','htsog','bs','bsc','canationalbroadcasts','gcl','gcl1','gs','r1','usnationalbroadcasts') 
      VALUES (':id',':ata',':atc',':atcommon',':atn',':ats',':atsog',':hta',':htc',':htcommon',':htn',':hts',':htsog',':bs',':bsc',':canationalbroadcasts',':gcl',':gcl1',':gs',':r1',':usNationalBroadcasts') 
      ON DUPLICATE KEY UPDATE id= ':id2'"; 
try { 
    $db = new PDO('db info'); 
    $db->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION); 
    $stmt = $db->prepare($query); 
    $stmt->bindParam(':ata', $ata, PDO::PARAM_STR); 
    $stmt->bindParam(':atc' , $atc , PDO::PARAM_STR); 
    $stmt->bindParam(':atcommon', $atCommon , PDO::PARAM_STR); 
    $stmt->bindParam(':atn', $atn , PDO::PARAM_STR); 
    $stmt->bindParam(':ats', $ats , PDO::PARAM_INT); 
    $stmt->bindParam(':atsog', $atsog , PDO::PARAM_INT); 
    $stmt->bindParam(':hta', $hta , PDO::PARAM_STR); 
    $stmt->bindParam(':htc', $htc , PDO::PARAM_STR); 
    $stmt->bindParam(':htcommon', $htCommon , PDO::PARAM_STR); 
    $stmt->bindParam(':htn', $htn , PDO::PARAM_STR); 
    $stmt->bindParam(':hts', $hts , PDO::PARAM_INT); 
    $stmt->bindParam(':htsog', $htsog , PDO::PARAM_INT); 
    $stmt->bindParam(':bs', $bs , PDO::PARAM_STR); 
    $stmt->bindParam(':bsc', $bsc , PDO::PARAM_STR); 
    $stmt->bindParam(':canationalbroadcasts', $caNationalBroadcasts , PDO::PARAM_STR); 
    $stmt->bindParam(':gcl', $glc , PDO::PARAM_BOOL); 
    $stmt->bindParam(':gcl1', $glc1 , PDO::PARAM_BOOL); 
    $stmt->bindParam(':gs', $gs , PDO::PARAM_INT);  
    $stmt->bindParam(':r1', $r1 , PDO::PARAM_BOOL); 
    $stmt->bindParam(':usnationalbroadcasts', $usNationalBroadcasts , PDO::PARAM_STR); 
    $stmt->bindParam(':id', $idGame , PDO::PARAM_INT); 
    $stmt->bindParam(':id2', $idGame , PDO::PARAM_INT); 
    $stmt->execute(); 
} catch (Exception $e) { 
     echo $e->getMessage(); 
     exit; 
    }

我似乎无法找到很多关于此错误消息，它与我的情况该怎么办。这段代码在解析jsonp的循环中...如果需要，我可以发布整个代码。

来源

2016-02-13 Kurt Leadley

是什么让你觉得SQLite支持这种语法？ –

它在哪里提到sqlite？ – RamRaider

使用准备好的语句时，不需要将您的参数包含在任何类型的引号内。这将通过发动机本身照顾：

$query = "INSERT INTO x(a,b,c,d) VALUES(:a, :b, :c, :d)";

来源

2016-02-13 07:36:36 hjpotter92

-1

正如@ HJPotter92注意 - 在SQL中的占位符不应该被引用，同时也应该注意到，字段名应该与反引号括起来，而不是单引号（或咱这名不属于保留&不包含空格等）

$query = "insert into results2015_2016 (
       `id`,`ata`,`atc`,`atcommon`,`atn`,`ats`,`atsog`,`hta`, 
       `htc`,`htcommon`,`htn`,`hts`,`htsog`,`bs`,`bsc`,`canationalbroadcasts`,`gcl`,`gcl1`, 
       `gs`,`r1`,`usnationalbroadcasts` 
     ) values (
      :id,:ata,:atc,:atcommon,:atn,:ats,:atsog,:hta,:htc,:htcommon,:htn,:hts, 
      :htsog,:bs,:bsc,:canationalbroadcasts,:gcl,:gcl1,:gs,:r1,:usnationalbroadcasts 
     ) on duplicate key update id=:id2";

来源

2016-02-13 08:06:24 RamRaider

PDO“在重复密钥更新”准备语句

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