获得一个ArrayIndexOutOfBoundsException

我有这样的代码：获得一个ArrayIndexOutOfBoundsException

public class OddSum1 { 
    public OddSum1() { 
    } 
    public static void main(String[] args) { 

    int OddLimit = Integer.parseInt(args[0]); 
    int sum = 0; 

    for (int i = 1; i <= OddLimit; i += 2) { 
    sum += i; 
    } 

    System.out.println("The sum of odd numbers from 1 to " + OddLimit + " is " + sum); 

    }  
}

每当我运行它，我得到这个错误：

java.lang.ArrayIndexOutOfBoundsException: 0 
    at OddSum1.main(OddSum1.java:7) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) 
    at java.lang.reflect.Method.invoke(Unknown Source) 
    at edu.rice.cs.drjava.model.compiler.JavacCompiler.runCommand(JavacCompiler.java:272)

它应该提示用户输入一个号码，然后从1总结奇数到输入的数字，我猜这是这个问题int OddLimit = Integer.parseInt(args[0]);

但我只是不知道如何解决它，任何帮助将是可怕的。

来源

2013-04-25 Capt' n Brian

可以采取任何从下面的两种方法的：

方法1：

代码：

public class OddSum1 { 
public OddSum1() { 
} 
public static void main(String[] args) { 
int OddLimit = Integer.parseInt(args[0]); 
int sum = 0; 
for (int i = 1; i <= OddLimit; i += 2) 
sum += i; 
System.out.println("The sum of odd numbers from 1 to " + OddLimit + " is " + sum); 
}  
}

可以通过将其作为参数传递给主方法作为指定oddLimit

要编译和运行代码：

javac OddSum1.java

java OddSum1 20

方法2：从提示

代码交互阅读OddLimit：

public class OddSum1 { 
public OddSum1() { 
} 
public static void main(String[] args) { 

int OddLimit = Integer.parseInt(System.console().readLine()); 
int sum = 0; 

for (int i = 1; i <= OddLimit; i += 2) 
sum += i; 

System.out.println("The sum of odd numbers from 1 to " + OddLimit + " is " + sum); 

} 
}

来源

2013-04-25 19:04:42 MSM