我已阅读关于copy or reference semantics for boost::spirt::qi::rule的其他线程。我正在使用Boost 1.42。在std :: list中存储boost :: spirit :: qi :: rule
using boost::spirit::qi::phrase_parse;
typedef boost::spirit::qi::rule < std::string::const_iterator, boost::spirit::ascii::space_type > rule_type;
std::list <rule_type> ruleList;
std::string const s("abcdef");
std::string::const_iterator iter = s.begin(), end = s.end();
std::cout << typeid(char_).name() << std::endl;
ruleList.push_back(char_);
ruleList.push_back(*ruleList.back());
assert(phrase_parse(iter, s.end(), ruleList.back(), boost::spirit::ascii::space));
assert(iter == s.end());
这种失败...
Assertion `phrase_parse(iter, s.end(), ruleList.back(), traits::space())' failed.
Aborted (core dumped)
有没有存储在STL列表或双端队列规则的方法吗? (引用不会死亡,直到删除)。