我的python libxml2根据我想要知道的内容,使用默认属性以不同方式处理文件。的例子中,使用DITA DTD(可以在包上www.dita-ot.org下载):作为期望展开默认(dita)属性
import libxml2
import libxsltmod
s = """<!DOCTYPE map PUBLIC "-//OASIS//DTD XDITA Map//EN"
"file://.../dita-ot-2.2.1/plugins/org.oasis-open.dita.v1
_2/dtd/technicalContent/dtd/map.dtd">
<map title="Empty map">
</map>"""
libxml2.substituteEntitiesDefault(1)
xmldoc = libxml2.parseDoc(s)
print xmldoc
输出:
<?xml version="1.0"?>
<!DOCTYPE map PUBLIC "-//OASIS//DTD XDITA Map//EN"
"file://.../dita-ot-2.2.1/plugins/org.oasis-open.dita.v1
_2/dtd/technicalContent/dtd/map.dtd">
<map xmlns:ditaarch="http://dita.oasis-open.org/architecture/2005/"
title="Empty map" ditaarch:DITAArchVersion="1.2" domains="(topic delay-d)
(map mapgroup-d) (topic indexing-d)
(map glossref-d) (topic hi-d)
(topic ut-d) (topic hazard-d)
(topic abbrev-d) (topic pr-d)
(topic sw-d) (topic ui-d)
" class="- map/map ">
</map>
但是,如果我注释掉import libxsltmod
,结果是:
<?xml version="1.0"?>
<!DOCTYPE map PUBLIC "-//OASIS//DTD XDITA Map//EN"
"file://.../dita-ot-2.2.1/plugins/org.oasis-open.dita.v
1_2/dtd/technicalContent/dtd/map.dtd">
<map title="Empty map">
</map>
因此,libxsltmod会使某些内容激活默认属性扩展。您能否提出建议,以及如何通过python激活此功能?
感谢您指向'readDoc'函数。但是,请更正您的答案,标记应该是'libxml2.XML_PARSE_NOENT | libxml2.XML_PARSE_DTDATTR' – olpa