如何一般设置属性配置？

Question

package com.xenoterracide.rpf.model.abstracts; 
import org.hibernate.annotations.Generated; 
import org.hibernate.annotations.GenerationTime; 
import org.springframework.data.domain.Persistable; 
import javax.persistence.Column; 
import javax.persistence.GeneratedValue; 
import javax.persistence.MappedSuperclass; 
import javax.validation.constraints.NotNull; 
import java.util.UUID; 

@MappedSuperclass 
public abstract class AbstractEntityBase extends AbstractPersistable<UUID> implements Persistable<UUID> { 
    // AbstractPersistable is a Copy of the Spring Data JPA version testing to see if I can fix this problem, 
    // also bug DATAJPA-622, plan to implement the spring variant if I can get it working with UUID 

    @NotNull 
    @Override 
    @Generated(GenerationTime.ALWAYS) 
    @GeneratedValue(generator = "entityIdGenerator") 
    @Column(columnDefinition = "uuid", updatable = false) 

    public UUID getId() { 
     return super.getId(); 
    } 
} 

这里是一个final类

@Entity 
@Table(name = "characters") 
class Character extends AbstractEntityBase { 
String name; 

@Override 
@Column(name = "character_id") 

public UUID getId() { 
    return super.getId(); 
} 

，但我得到这个错误

Caused by: org.hibernate.MappingException: Duplicate property mapping of id found in com.xenoterracide.rpf.model.character.Character 
at org.hibernate.mapping.PersistentClass.checkPropertyDuplication(PersistentClass.java:515) 
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:505) 
at org.hibernate.mapping.RootClass.validate(RootClass.java:270) 
at org.hibernate.cfg.Configuration.validate(Configuration.java:1358) 
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1849) 
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:850) 

我如何配置的AbstractPersistable的ID做正确的UUID和我想要的列名？同时使用AbstractPersistable，最好不需要重复说明我的最后一节课

更新我已经成功地通过@AttributeOverride做一些更新，但实际上我不是接近具有类（或其他外部final类）在AbstractPersistable和最终的类之间，可以用明智的方式做正确的事情。试图移动@GenericGenerator我package-info.java但随后停止承认通过该名称

@Entity 
@Table(name = "characters") 
@GenericGenerator(name = "uuid-generator", strategy = "uuid2") 
@AttributeOverride(
    name = "id", 
    column = @Column(
      name = "character_id", 
      insertable = false, 
      updatable = false, 
      unique = true, 
      nullable = false 
    )) 
class Character extends AbstractPersistable<UUID> implements Persistable<UUID> { 
String name; 

protected Character(final String name) { 
    this.name = name; 
} 

@SuppressWarnings("unused") 
protected Character() { 
} 

@Id 
@Override 
@Generated(GenerationTime.ALWAYS) 
@GeneratedValue(generator = "uuid-generator") 
public UUID getId() { 
    return super.getId(); 
} 

@NotNull 
@SuppressWarnings("unused") 
protected String getName() { 
    return name; 
} 

@SuppressWarnings("unused") 
protected void setName(String name) { 
    this.name = name; 
} 
} 

Answer 1

一个产生你在最后一节课覆盖ID：

@Override 
@Column(name = "character_id") 
public UUID getId() { 
    return super.getId(); 
} 

你可以让继承做到这一点！因此，您的最终课程必须如下所示：

@Entity 
@Table(name = "characters") 
class Character extends AbstractEntityBase { 
String name; 
} 

getId（）是从AbstractEntityBase类继承而来的。你将有一个uuid专栏和一个名字。

更新： 从Spring开始：“AbstractPersistable是一个非常基本用例的一站式商店，它唯一实际做的就是设置默认的id代码，如果你想自定义它，班上。” 因此，您的类AbstractEntityBase需要直接实现Persistable，这将纠正您的问题。

@MappedSuperclass 
public abstract class AbstractEntityBase implements Persistable<UUID> { 

    @Generated(GenerationTime.ALWAYS) 
    @GeneratedValue(generator = "entityIdGenerator") 
    @Column(columnDefinition = "uuid", updatable = false) 
    private UUID id; 

    // implements methods like hashcode or equals 
    .... 
}