联合表没有在JPA中创建？

Question

SOLUTION： 我已经想出了解决这个问题的方法。我使用shell脚本运行我的主类，并且还使用相同的shell脚本增强了我的所有类，这里是代码。

#!/bin/sh 
# 
# Compile and Run the OpenJPA test program 
# 
cp=. 
cp=$cp:lib/mysql-connector-java.jar 
cp=$cp:lib/openjpa-2.0.1.jar 
cp=$cp:lib/commons-lang-2.1.jar 
cp=$cp:lib/geronimo-jta_1.1_spec-1.1.1.jar 
cp=$cp:lib/serp-1.13.1.jar 
cp=$cp:lib/commons-collections-3.2.1.jar 
cp=$cp:lib/geronimo-jpa_2.0_spec-1.1.jar 
# 
echo "Compiling" 
javac -cp $cp *.java */*.java 
echo "Enhancing" 
java -cp $cp org.apache.openjpa.enhance.PCEnhancer nu/InstrumentType.java nu/Instrument.java nu/Laboratory.java nu/MedicalLaboratory.java 
echo "Running" 
java -cp $cp test 

正如你可以看到Nu是我的包的名字和我的类需要加强后跟/ 测试是我的主类。 我不知道，但增强这种方式，而不是使用建立在增强器作品ecplise。

QUESTION : 

这是我的文件层层次

我使用的OpenJPA

仪器，InstrumentType，实验室，MedicalLaboratory是我的班。 我已经在我的Instrument类和InstrumentType类中创建了连接的表/参考表，该类没有被创建。

我有我的仪表类中下面的代码

@ManyToOne 
    @JoinColumn(name="type", nullable=false) 
    public InstrumentType type; 


    @ManyToMany(fetch=EAGER) 
    @JoinTable(name="usedBy", 
      joinColumns=@JoinColumn(name="instrument"), 
      inverseJoinColumns=@JoinColumn(name="laboratory")) 
    public Set<Laboratory> UsedBy; 

public void setUsedBy(Set<Laboratory> UsedBy) { 
    this.UsedBy = UsedBy; 
    } 

我有我的InstrumentType类

@ElementCollection(fetch=EAGER) 
    @Column(name="name") 
    @CollectionTable(name="InstrumentName", joinColumns=@JoinColumn(name="type")) 
    public Set<String> names; 

这是即我能看到表的输出中下面的代码我的Navicat。正如你所看到的，只有4个表正在创建，而不是连接表。

这是我的主类

public class main { 

    @SuppressWarnings("unchecked") 
    public static void main(String[] args) { 

    // Create the new objects to be persisted. 
    Instrument i = new Instrument(); 
    InstrumentType it = new InstrumentType(); 
    Laboratory l = new Laboratory(); 
    MedicalLaboratory ml = new MedicalLaboratory(); 


    // Configure and create the factory. 
    java.util.Map<Object,Object> map = new java.util.HashMap<Object,Object>(); 
    map.put("openjpa.ConnectionUserName", "root"); 
    map.put("openjpa.ConnectionPassword", "root"); 
    map.put("openjpa.ConnectionURL", "jdbc:mysql://127.0.0.1:3306/test123"); 
    map.put("openjpa.ConnectionDriverName", "com.mysql.jdbc.Driver"); 
    map.put("openjpa.jdbc.SynchronizeMappings", "buildSchema"); 
     EntityManagerFactory factory = Persistence.createEntityManagerFactory("test123", map); 

     // Create a new EntityManager from the EntityManagerFactory. The 
     // EntityManager is the main object in the persistence API, and is 
     // used to create, delete, and query objects, as well as access 
     // the current transaction 
     EntityManager em = factory.createEntityManager(); 

     // Begin a new local transaction so that we can persist a new entity 
     em.getTransaction().begin(); 

     // Create and persist a new Message entity 
     em.persist(i); 
     em.persist(it); 
     em.persist(l); 
     em.persist(ml); 


     // Commit the transaction, which will cause the entity to 
     // be stored in the database 
     em.getTransaction().commit(); 

     // It is always good practice to close the EntityManager so that 
     // resources are conserved. 
     em.close(); 
     factory.close(); 

} 
} 

这是我越来越无法理解的错误。

73 test123 INFO [main] openjpa.Runtime - Starting OpenJPA 2.0.1 
164 test123 INFO [main] openjpa.jdbc.JDBC - Using dictionary class "org.apache.openjpa.jdbc.sql.MySQLDictionary". 
Exception in thread "main" <openjpa-2.0.1-r422266:989424 fatal store error> org.apache.openjpa.persistence.RollbackException: null 
    at org.apache.openjpa.persistence.EntityManagerImpl.commit(EntityManagerImpl.java:584) 
    at nu.main.main(main.java:50) 
Caused by: <openjpa-2.0.1-r422266:989424 nonfatal general error> org.apache.openjpa.persistence.PersistenceException: null 
    at org.apache.openjpa.kernel.BrokerImpl.beforeCompletion(BrokerImpl.java:1963) 
    at org.apache.openjpa.kernel.LocalManagedRuntime.commit(LocalManagedRuntime.java:81) 
    at org.apache.openjpa.kernel.BrokerImpl.commit(BrokerImpl.java:1479) 
    at org.apache.openjpa.kernel.DelegatingBroker.commit(DelegatingBroker.java:925) 
    at org.apache.openjpa.persistence.EntityManagerImpl.commit(EntityManagerImpl.java:560) 
    ... 1 more 
Caused by: java.lang.IllegalArgumentException 
    at nu.MedicalLaboratory.pcProvideField(MedicalLaboratory.java) 
    at org.apache.openjpa.kernel.StateManagerImpl.provideField(StateManagerImpl.java:3135) 
    at org.apache.openjpa.kernel.StateManagerImpl.preFlush(StateManagerImpl.java:2956) 
    at org.apache.openjpa.kernel.PNewState.beforeFlush(PNewState.java:40) 
    at org.apache.openjpa.kernel.StateManagerImpl.beforeFlush(StateManagerImpl.java:1047) 
    at org.apache.openjpa.kernel.BrokerImpl.flush(BrokerImpl.java:2077) 
    at org.apache.openjpa.kernel.BrokerImpl.flushSafe(BrokerImpl.java:2037) 
    at org.apache.openjpa.kernel.BrokerImpl.beforeCompletion(BrokerImpl.java:1955) 
    ... 5 more 

我只是试图去显示的连接表，这样我可以对他们进行查询。如果有人能指出为什么连接表没有被创建，那将是非常好的。

Answer 1

你目前已经被指出在以下例外的线路问题：

at org.apache.openjpa.persistence.EntityManagerImpl.commit(EntityManagerImpl.java:560) 
    ... 1 more 
Caused by: java.lang.IllegalArgumentException 
    at nu.MedicalLaboratory.pcProvideField(MedicalLaboratory.java) 

你能后，你有充分的映射类，还存在哪些实体关系你试图映射？你应该先建立一个ER类，没有ER域，然后选择'最简单的'ER关系，然后映射下一个。它从你的清单中不清楚，什么正在映射？