在休眠

如何更新复合键我有8列C1，C2，C3，C4，C5，C6，C7，C8，其中的{C1，C2，C3}组合是一个表一个复合键。在休眠

我想更新只有C2的数据，但是当我尝试更新它的显示异常：

org.hibernate.StaleStateException: Batch update returned unexpected row count from update: 0 actual row count: 0 expected: 1 
at org.hibernate.jdbc.BatchingBatcher.checkRowCount(BatchingBatcher.java:93) 
at org.hibernate.jdbc.BatchingBatcher.checkRowCounts(BatchingBatcher.java:79) 
at org.hibernate.jdbc.BatchingBatcher.doExecuteBatch(BatchingBatcher.java:58) 
at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:195) 
at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:230) 
at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:141) 
at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:296) 
at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27) 
at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1007)

是否有可能在Hibernate来更新这个？

我使用的代码 -

public static synchronized Session getSession() { 

    Session mysession = (Session) DAO.session.get(); 
    if (mysession == null||!mysession.isOpen()) { 
     mysession = sessionFactory.openSession(); 
     DAO.session.set(mysession); 
    } 

    return mysession; 
} 

protected void begin() { 
     try{ 

    getSession().beginTransaction(); 

     }catch(Exception ex) 
     { 
      LOGGER.error(ex); 
     } 
} public void update(Facebook facebookdata){ begin(); 
     getSession().update(facebookdata); 
     commit();

}

来源

2011-06-23 Khoyendra Pande

无法更新关系数据库中的主键列。也许你可以使用代理键？ –