画我试着在此纹理绘制字符串:翻转的NSString在CGContext上
http://picasaweb.google.it/lh/photo/LkYWBv_S_9v2d6BAfbrhag?feat=directlink
但是绿色的数字似乎垂直翻转。 我已经建立了我这样背景:
colorSpace = CGColorSpaceCreateDeviceRGB();
data = malloc(height * width * 4);
context = CGBitmapContextCreate(data, width, height, 8, 4 * width, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big);
,我已经绘制字符串:
UIGraphicsPushContext(context);
for(int i=0;i<packs.size();++i)
{
CGPoint points[4] =
{
gltextures[i].texCoords[0] * size.width, //0
gltextures[i].texCoords[1] * size.height, //1
gltextures[i].texCoords[2] * size.width, //2
gltextures[i].texCoords[3] * size.height, //3
gltextures[i].texCoords[4] * size.width, //4
gltextures[i].texCoords[5] * size.height, //5
gltextures[i].texCoords[6] * size.width, //6
gltextures[i].texCoords[7] * size.height //7
};
CGRect debugRect = CGRectMake
(
gltextures[i].texCoords[0] * size.width,
gltextures[i].texCoords[1] * size.height,
gltextures[i].width,
gltextures[i].height
);
CGContextSetStrokeColorWithColor(context, [[UIColor redColor] CGColor]);
CGContextAddLines(context, points, 4);
CGContextClosePath(context);
CGContextDrawPath(context, kCGPathStroke);
NSString* s = [NSString stringWithFormat:@"%d",gltextures[i].texID];
UIFont* font = [UIFont fontWithName:@"Arial" size:12];
CGContextSetRGBFillColor(context, 0, 1, 0, 1);
[s drawAtPoint:points[0] withFont:font];
}
UIGraphicsPopContext();
变换矩阵似乎身份矩阵...没有CGAffineTransform应用于此背景下。 如果字符串翻转,也许,我的所有图像翻转! 有什么建议吗?
PS:抱歉,我的英语)