在python中通过\n\n
拆分字符串的最简单方法是什么?如何解析一个zcat输出
这是我的原始字符串,其来源于http://ftp2.de.debian.org/debian/dists/stable/main/binary-i386/Packages.gz
Package: zziplib-bin\n
Priority: optional\n
Section: utils\n
Installed-Size: 116\n
Maintainer: LIU Qi <[email protected]>\n
Architecture: i386\n
Source: zziplib (0.13.56-1)\n
Version: 0.13.56-1+b1\n
...\n
\n
Package: zzuf\n
Priority: optional\n
Section: devel\n
Installed-Size: 228\n
Maintainer: Sam Hocevar <[email protected]>\n
Architecture: i386\n
Version: 0.13.svn20100215-2\n
...\n
\n
ZCAT输出也许任何你曾经做过这个
这应该最好是这样的:
{
"zziplib-bin": {"Version": "0.13.56-1+b1"},
"zzuf": {"Version": "0.13.svn20100215-2"},
...
}
- Timo