Json解析没有根对象

我想获得特定婚礼或仪式的Photo_name。

我想保留一些照片名称的婚礼和其他照片名称阵列名称。

{ 
-f1: { 
     Photos: { 
      Wedding: [ 
        { 
        Photo_id: "99", 
        Photo_name: "2WLB4cSJtg.jpg", 
        User_id: "11", 
        Date: "0000-00-00" 
        }, 
        { 
        Photo_id: "97", 
        Photo_name: "EjOCbkWwmF.jpg", 
        User_id: "11", 
        Date: "0000-00-00" 
        }, 
        { 
        Photo_id: "90", 
        Photo_name:"18e7af197f2060ad1c58d95c38f16ecc.jpg", 
        User_id: "11", 
        Date: "2013-07-24" 
        } 
        ], 
     Ceremony: [ 
        { 
        Photo_id: "96", 
        Photo_name: "hTWiAQUDnL.jpg", 
        User_id: "11", 
        Date: "0000-00-00" 
        }, 
        { 
        Photo_id: "92", 
        Photo_name: "529753_425904027490910_737057237_n.jpg", 
        User_id: "11", 
        Date: "2013-07-24" 
        }, 
        { 
        Photo_id: "93", 
        Photo_name: "yCbKG8txQY.jpg", 
        User_id: "11", 
        Date: "0000-00-00" 
        }, 
        { 
        Photo_id: "94", 
        Photo_name: "k9goxnlscT.jpg", 
        User_id: "11", 
        Date: "0000-00-00" 
        }, 

       ] 
      } 
     } 
    }

此代码给我F1键并显示JSON的一切，值：

NSString *str=[[NSString alloc]initWithBytes:[webdata mutableBytes] length:[webdata length] encoding:NSUTF8StringEncoding]; 

    NSMutableDictionary *result = [NSJSONSerialization JSONObjectWithData:[str dataUsingEncoding:NSUTF8StringEncoding] options:0 error:nil]; 
    for (id thekey in result) { 
     NSLog(@"KEY %@ VALUE %@",thekey,[result valueForKey:thekey]); 

    }

来源

2013-07-24 Chitra Khatri

json显示无效 –

其有效..它与Android一起使用 –

当且仅当密钥必须包含“”和“，”在末尾时才有效 –

NSString *str=[[NSString alloc]initWithBytes:[webdata mutableBytes] length:[webdata length] encoding:NSUTF8StringEncoding]; 

NSMutableDictionary *result = [NSJSONSerialization JSONObjectWithData:[str dataUsingEncoding:NSUTF8StringEncoding] options:0 error:nil]; 


NSArray *weddingPhotos = [[[[result valueForKey:@"f1"] valueForKey:@"Photos"] valueForKey:@"Wedding"] valueForKeyPath:@"Photo_name"]; 
NSLog(@"%@",weddingPhotos); 

NSArray *ceremonyPhotos = [[[[result valueForKey:@"f1"] valueForKey:@"Photos"] valueForKey:@"Ceremony"] valueForKeyPath:@"Photo_name"]; 
NSLog(@"%@",ceremonyPhotos);

试试这个。（未测试）

来源

2013-07-24 09:34:02

@ChitraKhatri URW :) –

只需说{}是一个字典和[]给你NSArray.So你有valueForKey:方法

所以

NSDictionary *dict = [jsonData objectForKey:@"-f1"] ; 
NSDictionary *photosDict = [dict objectForKey:@"Photos"] ; 
NSArray *weddingPhotos = [photosDict objectForKey:@"Wedding"] ; // array of dict

到达品脱throught所有对象和数组

来源

2013-07-24 09:35:46

Json解析没有根对象

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